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solong [7]
3 years ago
9

Example of a biochemical sedimentary rock that is rich in carbon

Chemistry
1 answer:
stira [4]3 years ago
5 0
Limestone is an example
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Identify the various types of fossil fuels helppp​
docker41 [41]

Answer: hehe its kirishima here and the various types of fossil fuels are energy provision coal, oil and natural gas. Coal is a solid fossil fuel formed over millions of years by decay of land vegetation.

haha hope this helped

-yours truly red riot

8 0
3 years ago
4.13 moles of chromium (III) nitride weighs how much?
Leya [2.2K]

Answer: 272.5915639999...

Explanation:

3 0
3 years ago
Which identifies an oxidation-reduction reaction?
Strike441 [17]

Answer:

Explanation:

The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining or losing the electrons and oxidation state of elements are changed.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄  →  Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is  also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized

8 0
3 years ago
Need help with 14 and 16 pls asap!! this is my friends test and im taking it tomorrow!!
marin [14]

Answer:

Q14: 17,140 g = 17.14 kg.

Q16: 504 J.

Explanation:

<u><em>Q14:</em></u>

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by ice (Q = 3600 x 10³ J).

m is the mass of the ice (m = ??? g).

c is the specific heat of the ice (c of ice = 2.1 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 100.0°C - 0.0°C = 100.0°C).

∵ Q = m.c.ΔT

∴ (3600 x 10³ J) = m.(2.1 J/g.°C).(100.0°C)

∴ m = (3600 x 10³ J)/(2.1 J/g.°C).(100.0°C) = 17,140 g = 17.14 kg.

<u><em>Q16:</em></u>

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by ice (Q = ??? J).

m is the mass of the ice (m = 12.0 g).

c is the specific heat of the ice (c of ice = 2.1 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 0.0°C - (-20.0°C) = 20.0°C).

∴ Q = m.c.ΔT = (12.0 g)(2.1 J/g.°C)(20.0°C) = 504 J.

6 0
3 years ago
Classify the bonds formed between each pair as ionic, polar covalent, or nonpolar covalent based solely on each element's positi
Amanda [17]
<span>you have to find the differences of electronegativity for the atoms joined by the bond. if their diff is <0.4,
then it's non-polar if it's between 0.4 to 1.7
then it's polar 1.7 and up it's ionic Electronegativity values can be found on most periodic tables.</span>
5 0
3 years ago
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