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2 years ago

Please help with this

Chemistry

2 answers:

lord [1]2 years ago

7 0

Choose all options that apply . Which of the following are steps necessary to ensure patient safety ? a) Make sure that the medication is dispensed in the same units in which it was prescribed. b ) Review any calculation questions with the pharmacist . Check to see if there's a better medication for the patient's problem. d) Dispense an extra dose to save the patient from having to return in case of loss or damage to one of the doses. Oe ) Compare the label on the medication with the order from the physician .

dlinn [17]2 years ago

5 0

Answer:

A sample of a gas (5.0 mol) at 1.0 atm is expanded at constant temperature from 10 L to 15 L. The final pressure is 0.67 atm.

Step by Step Explanation?

Boyle's law states that in constant temperature the variation volume of gas is inversely proportional to the applied pressure.

The formula is,

P₁ x V₁ = P₂ × V₂

Where,

P₁ is initial pressure = 1 atm

P2 is final pressure = ? (Not Known)

V₁ is initial volume = 10 L

V₂ is final volume = 15 L

Now put the values in the formula,

\begin{gathered}\rm 1\times 10 = P_2\times 15\\\\\rm P_2 = \frac{10}{15\\} \\\\\rm P_2 = 0.67\end{gathered]

Therefore, the answer is 0.67 atm.

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Using complete sentences, explain how to predict the products and balance the reaction between sulfuric acid and potassium hydro

Dahasolnce [82]

The product(s) of the reaction are to be determined given the reactants, sulfuric acid and potassium hydroxide. sulfuric acid is an acid, whereas potassium hydroxide is a basic. The results of this neutralizing process are salt and water.

<h3>What is the reaction between sulfuric acid and potassium hydroxide?</h3>

The result will be, H+ from H₂SO₄ reacts with OH- from KOH to generate H₂O. Also, K+ reacts with SO₄²⁻ to create K₂SO4₄

As a result, the balanced equation will be:

$\rm H_2SO_4 + 2KOH --- > K_2SO_4 + 2H_2O$

Thus, the product(s) of the reaction are to be determined given the reactants, sulfuric acid and potassium hydroxide. Sulfuric acid is an acid, whereas potassium hydroxide is a basic. The results of this neutralizing process are salt and water.

Learn more about potassium hydroxide

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6 0

3 years ago

If the heat released during condensation goes only to warming the iron block, what is the final temperature (in ∘C) of the iron

OLga [1]

Answer:

$91°C$

Explanation:

CHECK THE COMPLETE QUESTION BELOW;

Suppose that 0.95 g of water condenses on a 75.0 g block of iron that is initially at 22 Â°c. if the heat released during condensation is used only to warm the iron block, what is the final temperature (in Â°c) of the iron block? (assume a constant enthalpy of vaporization for water of 44.0 kj/mol.)

Heat capacity which is the amount of heat required to raise the temperature of an object or a substance by one degree

From the question, it was said that that 0.95 g of water condenses on the block thenwe know that Heat evolved during condensation is equal to the heat absorbed by iron block.

Then number of moles =given mass/ molecular mass

Molecular mass of water= 18 g/mol

Given mass= 0.95 g

( 0.95 g/18 g/mol)

= 0.053 moles

Then Heat evolved during condensation = moles of water x Latent heat of vaporization

Q= heat absorbed or released

H=enthalpy of vaporization for water

n= number of moles

Q=nΔH

Q = 0.053 moles x 44.0 kJ/mol

= 2.322 Kj

=2322J

We can now calculate Heat gained by Iron block

Q = mCΔT

m = mass of substance

c = specific heat capacity

=change in temperature

m = 75 g

c = 0.450 J/g/°C

If we substitute into the above formula we have

Q= 75 x 0.450 x ΔT

2322 = 75 x 0.450 x ΔT

ΔT = 68.8°C

Since we know the difference in temperature, we can calculate the final temperature

ΔT = T2 - T1

T1= Initial temperature = 22°C

T2= final temperature

ΔT= change in temperature

T2 = T1+ ΔT

= 68.8 + 22

= 90.8 °C

=91°C

Therefore, final temperature is $91°C$

6 0

3 years ago

3S8 + 8 OH- + 8 S3 + 4 HOOH

NemiM [27]

Answer:

Second order

Explanation:

We could obtain the order of reaction by looking at the table very closely.

Now notice that in experiment 1 and 2, the concentration of [OH^-] was held constant while the concentration of [S8] was varied. So we have;

a situation in which the rate of reaction was tripled;

0.3/0.1 = 2.10/0.699

3^1 = 3^1

Therefore the order of reaction with respect to [S8] is 1.

For [OH^-], we have to look at experiment 2 and 3 where the concentration of [S8] was held constant;

x/0.01 = 4.19/2.10

x/0.01 = 2

x = 2 * 0.01

x = 0.02

So we have;

0.02/0.01 = 2^1

2^1 = 2^1

The order of reaction with respect to [OH^-] = 1

So we have the overall rate law as;

Rate = k[S8]^1 [OH^-] ^1

Overall order of reaction = 1 + 1 = 2

Therefore the reaction is second order.

4 0

3 years ago

Which statement best describes why modern horses look the way they do?

Tasya [4]

Answer:

Explanation:

7 0

3 years ago

Provide the reagents necessary to convert (S)-3-methyl-3-phenylpentanoic acid to (5)-3-methyl-3-phenylpentanamine.

8090 [49]

Answer:

1. SOCl2/pyridine

2. NH3

3. LiAlH4

4. H2O

Explanation:

In the conversion of (S)-3-methyl-3-phenylpentanoic acid to (5)-3-methyl-3-phenylpentanamine, SOCl2/pyridine is first added to the (S)-3-methyl-3-phenylpentanoic acid

This is then followed by the addition of NH3 is subsequently added followed by reduction using LiAlH4 which reduces the carbonyl carbon to an alkane. addition of water completes the mechanism and leads to the formation of the product.

3 0

3 years ago