Ask question

Ask question

All categories

4 years ago

5

Help ASAP pleaseeee!

1 answer:

Bond [772]4 years ago

5 0

Answer:

When plastics decomposed, they produce methane gas, which contributes to global warming (not questioning beliefs on the matter). Plastic debris also is an issue affecting the ecology of an environment and can cause issues for the affected organisms. But the greenhouse gases released from biodegradable plastics is likely a greater concern.

You might be interested in

Fluorine gas is placed in contact with calcium metal at high temperatures to produce calcium fluoride powder. What is the formul

Rudik [331]

F₂(g) + Ca(s) → CaF₂(s)

5 0

4 years ago

Read 2 more answers

How have forests been exploited by humans

Anuta_ua [19.1K]

I hope this will help you

3 0

3 years ago

A sample of O2(g) is placed in an otherwise empty, rigid container at 4224 K at an initial pressure of 4.97 atm, where it decomp

frutty [35]

Answer:

The value of $K_p$ at 4224 K is 314.23.

Explanation:

$O_2(g)\rightleftharpoons 2O(g)$

Initially

4.97 atm 0

At equilibrium

4.97 - p 2p

At initial stage, the partial pressure of oxygen gas = =4.97 atm

At equilibrium, the partial pressure of oxygen gas = $p_{O_2}=0.28 atm$

So, 4.97 - p = 0.28 atm

p = 4.69 atm

At equilibrium, the partial pressure of O gas = $p_{O}=2p=2\times 4.69 atm=9.38 atm$

The expression of $K_p$ is given as :

$K_p=\frac{(p_{O})^2}{(p_{O_2})}$

$K_p=\frac{(9.38 atm)^2}{0.28 atm}=314.23$

The value of $K_p$ at 4224 K is 314.23.

5 0

3 years ago

The atomic symbol superscript 40 subscript 19 upper k. represents potassium-40 (k-40), a radioactive isotope that has 19 protons

Oksana_A [137]

Answer:

40/18AR

Explanation:

sorry my answer was late but i hope this helps someone else! I got it right on the test

8 0

2 years ago

If 18 mL of methanol is used to make an aqueous solution that is 15% methanol by volume, how many mL of solution is produced?

Yuri [45]

Answer:

120.0 mL.

Explanation:

As it is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.

We suppose that the initial W% of methanol is 100.0 %

<em>∴ (W%V) before dilution = (W%V) after dilution.</em>

W% before dilution = 100.0 %, V before dilution = 18.0 mL.

W% after dilution = 15.0 %, V after dilution = ??? mL.

<em>∴ V after dilution = (W%V) before dilution/W% after dilution = </em>(100.0 %)(18.0 mL)/(15.0%)<em> = 120.0 mL.</em>

7 0

3 years ago