In water, what happens to a base?

You have a strong solution of lemonade that you need to dilute before serving. During the dilution which of the following will c

Nadusha1986 [10]

Answer:

If you have to choose only one answer, it is B.

Explanation:

Adding water - changes the volume of solvent

Number of moles of solute does not change because you do not adding solute.

the Molarity of solvent usually is not used.

If it is only one choice, it is B.

7 0

3 years ago

A zinc rod is placed in 0.1 MZnSO4 solution at 298 K. Write the electrode reaction and calculate the potential of the electrode.

yanalaym [24]

<u>Answer:</u> The potential of electrode is -0.79 V

<u>Explanation:</u>

When zinc is dipped in zinc sulfate solution, the electrode formed is $Zn^{2+}(aq.)/Zn(s)$

Reduction reaction follows: $Zn^{2+}(0.1M)+2e^-\rightarrow Zn(s);(E^o_{Zn^{2+}/Zn}=-0.76V)$

To calculate the potential of electrode, we use the equation given by Nernst equation:

$E_{(Zn^{2+}/Zn)}=E^o_{(Zn^{2+}/Zn)}-\frac{0.059}{n}\log \frac{[Zn]}{[Zn^{2+}]}$

where,

$E_{cell}$ = electrode potential of the cell = ?V

$E^o_{cell}$ = standard electrode potential of the cell = -0.76 V

n = number of electrons exchanged = 2

$[Zn]=1M$ (concentration of pure solids are taken as 1)

$[Zn^{2+}]=0.1M$

Putting values in above equation, we get:

$E_{cell}=-0.76-\frac{0.059}{2}\times \log(\frac{1}{0.1})\\\\E_{cell}=-0.79V$

Hence, the potential of electrode is -0.79 V

4 0

3 years ago

What is the average of the two weights of a nickel and dime. Dime is 2.26g and nickel is 4.97g?

ANTONII [103]

Dime=2.26g
Nickel=4.97g

$\\ \rm\Rrightarrow Avg\:Weight=\dfrac{Sum\:of\:Weights}{No\:of\:weights}$

$\\ \rm\Rrightarrow Avg\:weight=\dfrac{2.26+4.96}{2}$

$\\ \rm\Rrightarrow Avg\;weight=\dfrac{7.23}{2}$

$\\ \rm\Rrightarrow Avg\:Weight=3.6g$

5 0

2 years ago

Which observations is the best evidence that unknown liquid X is a composed of only pure substance

Angelina_Jolie [31]

Answer:

A substance that is composed only of atoms having the same atomic number is ... 36 grams of an unknown liquid at its boiling point,.

4 0

2 years ago

Substance A has the following properties.

ella [17]

It will take 1.11 min to heat the sample to its melting point.

Melting point = - 20°C

Boiling point = 85°C

∆H of fusion = 180 J/g

∆H of vap = 500 J/g

C(solid) = 1.0 J/g °C

C(liquid) = 2.5 J/g °C

C(gas) = 0.5 J/g °C

Mass of sample = 25 g

Initial temperature = - 40°C

Final temperature = 100°C

Rate of heating = 450 J/min

Specific heat capacity formula:- q = m ×C×∆T

Here, q = heat energy

m = mass

C = specific heat

∆T = temperature change

Melting point = - 20°C

C(solid) = 1.0 J/g °C

∆T = final temperature - initial temperature = -20 - (-40) = 20

Put these value in Specific heat capacity formula

q = m ×C×∆T

q = 25×1.0×20

=500J

The Rate of heating = 450 J/min

i.e. 450J = 1min

so, 500J = 1.11min

1.11 minutes does it take to heat the sample to its melting point.

The specific heat capacity is defined as the amount of heat absorbed in line with unit mass of the material whilst its temperature increases 1 °C.

Learn more about specific heat capacity here:- brainly.com/question/26866234

#SPJ4

3 0

1 year ago