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dem82 [27]
3 years ago
7

Describe the structure of ammonium lauryl sulfate. Refer to the given diagram. Your answer should include the type of bonding, t

he elements contained, and the size and shape of the molecule. Write a short paragraph.

Chemistry
1 answer:
Mariana [72]3 years ago
3 0

Explanation:

Ammonium lauryl sulfate (ALS) is the common name for ammonium dodecyl sulfate (CH3(CH2)10CH2OSO3NH4). The anion consists of a nonpolar hydrocarbon chain and a polar sulfate end group. The combination of nonpolar and polar groups confers surfactant properties to the anion: it facilitates the dissolution of both polar and non-polar materials. ALS is classified as a sulfate ester. It is found primarily in shampoos and body wash as a foaming agent. Lauryl sulfates are very high-foam surfactants that disrupt the surface tension of water in part by forming micelles at the surface-air interface.

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What is the method use to separate sand and water​
Slav-nsk [51]

Sand and water can be separated by any of the following methods:

1. Sedimentation and decantation: This method involves the mixture being kept undisturbed for some time. After some time, sand being heavier and insoluble in water, settles down at the bottom of container. Now, water is poured into another container to separate it from sand.

2. Filtration: This method involves the mixture being passed through a filter paper (a filter with very fine pores). Sand particles being larger in size are retained by the filter paper and get separated from water.

I hope this helps! :D

7 0
3 years ago
What volume of CH4(g), measured at 25oC and 745 Torr, must be burned in excess oxygen to release 1.00 x 106 kJ of heat to the su
anastassius [24]

Answer:

V=27992L=28.00m^3

Explanation:

Hello,

In this case, the combustion of methane is shown below:

CH_4+2O_2\rightarrow CO_2+2H_2O

And has a heat of combustion of −890.8 kJ/mol, for which the burnt moles are:

n_{CH_4}=\frac{-1.00x10^6kJ}{-890.8kJ/mol}= 1122.6molCH_4

Whereas is consider the total released heat to the surroundings (negative as it is exiting heat) and the aforementioned heat of combustion. Then, by using the ideal gas equation, we are able to compute the volume at 25 °C (298K) and 745 torr (0.98 atm) that must be measured:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{1122.6mol*0.082\frac{atm*L}{mol*K}*298K}{0.98atm}\\\\V=27992L=28.00m^3

Best regards.

8 0
4 years ago
correctly stated hypothesis for the below question. The correct formate is "if______ then______ because______"​
ankoles [38]

Answer:

That is the correct form for a hypothesis.

Explanation:

4 0
3 years ago
The coefficients that balance the following equation NaCl + MgBr2 →→ MgCl2 + NaBr are
levacccp [35]
I believe the answer is C
6 0
3 years ago
At which temperature and pressure would a sample of helium behave most like an ideal gas?
musickatia [10]

Here we have to get the temperature and pressure at which helium gas mostly behaves as ideal gas.

Helium (He) behave most like an ideal gas upto 24K temperature and 0 atm pressure.

The deviation of a real gas to ideal gas occurs at high temperature and low pressure.

The deviation of ideal gas to real gas occurs on taking into account the van der waals' force of attraction between the gas molecules. Now, the van der waals' interaction depends upon the polarisibility of the gas molecule.

As helium (He) is non-polarisable and very small (atomic number 2) it mostly behaves as ideal gas upto 24K temperature and 0 atm pressure.

Although the deviation from the ideal gas behavior to real gas is not so prominent at little high temperature also. Upto 50K it mostly behaves like an ideal gas.    

6 0
3 years ago
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