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love history [14]
3 years ago
5

How many molecules are there in 42gms of Na?

Chemistry
1 answer:
REY [17]3 years ago
4 0
There should be 1.8 mol Na
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How many molecules are in 5 moles of C10H210?
Pavlova-9 [17]

Answer:

3.0 x 10²⁴molecules

Explanation:

Given parameters:

Number of moles of compound  = 5moles

Unknown:

Number of molecules  = ?

Solution:

A mole is substance that contains the Avogadro's number of particles;

   1 mole  = 6.02 x 10²³ molecules

   5 moles of the compound will give 5 x 6.02 x 10²³ molecules

                = 3.0 x 10²⁴molecules

3 0
3 years ago
A gas has a pressure of 550 kPa at 327°C. What will its pressure be at 27°C, if the volume does not change?
lozanna [386]

Answer:

300°

Explanation:

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3 years ago
Network forensics might deal with what? Retrieving photos from a PC Analyzing text messages Investigating a data breach Defragme
balandron [24]

Answer:

Investigating a data breach

Explanation:

A data breach usually involves data exfiltration over a computer network. the other options involve data being stored on a device locally which isn't volatile data like text messages, photos or rearranging data in defragmentation all of which does not require a network.

8 0
3 years ago
A 5.00 L sample of helium expands to 12.0 L at which point the
mina [271]

Answer:

1.73 atm

Explanation:

Given data:

Initial volume of helium = 5.00 L

Final volume of helium = 12.0 L

Final pressure = 0.720 atm

Initial pressure = ?

Solution:

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

P₁ × 5.00 L = 0.720 atm × 12.0 L

P₁ = 8.64 atm. L/5 L

P₁ = 1.73 atm

7 0
3 years ago
What is the mass of 975 mL of mercury? Its density is 13.5 g/mL
miss Akunina [59]

Answer:

72.22 g

Explanation:

975 mL Mercury× 13.5 g/mL = 72.22 g

7 0
3 years ago
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