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Kobotan [32]
3 years ago
11

Are you weightless when you go upwards in an elevator.Explain using newtons 3rd law of motion

Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
6 0

Answer:

yes

Explanation:

inside the free falling elevator you and the scale are both in free fall. because the only force acting on you is gravity, the scale is no longer pushing up on you. according to Newton's 3rd law you no longer push down on the scale so the scale pointer stays at zero making you seem weightless .

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How many moles of oxygen gas would be needed to completely burn 8 moles of<br> hydrogen sulfide?
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12 mol O2

Explanation:

This is assuming you're using a combustion equation of

2 H2S + 3O2 -> 2H2O + 2SO2

Next time include the equation because that is where you will find your mol to mol ratio

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Find energy is the wavelength is 5.2x10^-7m (Show work)
RoseWind [281]

Answer:

E = 3.825×10⁻¹⁹ J

Explanation:

Wavelength of photon = 5.2 ×10⁻⁷m

Energy of photon = ?

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E = hc/λ

h = plancks constant = 6.63×10⁻³⁴ Js

c = speed of wave = 3×10⁸ m/s

by putting values,

E = 6.63×10⁻³⁴ Js ×3×10⁸ m/s / 5.2 ×10⁻⁷m

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4 0
3 years ago
In the reaction of silver nitrate with sodium chloride, how many grams of silver chloride will be produced from 100. g of silver
pantera1 [17]

Answer:

The mass in grams of silver chloride, AgCl produced is 84.37 grams

Explanation:

The chemical equation for the reaction is given as follows;

AgNO₃ + NaCl   →  AgCl + NaNO₃

The mass of silver nitrate, AgNO₃, in the reaction = 100.0 g

Therefore, 1 Mole of AgNO₃ produces 1 mole of AgCl,

The molar mass of silver nitrate, AgNO₃ = 169.87 g/mol

The number of moles of silver nitrate, AgNO₃, in the reaction = 100/169.87 moles

The number of moles of silver nitrate, AgNO₃, in the reaction ≈ 0.59 moles

Since 1 mole of AgNO₃ produces 1 mole of AgCl, 0.59 moles of AgNO₃ produces 0.59 moles of AgCl

The number of moles of silver chloride, AgCl produced = 0.59 moles

The molar mass of silver chloride, AgCl = 143.32 g/mol

Therefore;

The mass of silver chloride, AgCl produced = The number of moles of silver chloride, AgCl produced × The molar mass of silver chloride, AgCl

Which gives;

The mass of silver chloride, AgCl produced = 143.32 g/mol × 0.59 moles = 84.37 g

The mass of silver chloride, AgCl produced = 84.37 g.

7 0
3 years ago
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