Hello!
Percentage error = (true value - measured value)/true value x 100%
Percentage error = (27.7-27.0)/27.7 x100% = 25.3%
Hi!
When titrating Calcium and Water solution, if there is some CaCO3 in the solution, the following reactions may occur in acid solution:
CaCO₃ + H⁺ → Ca⁺² + HCO₃⁻
HCO₃⁻ + H⁺ ↔ H₂CO₃ → CO₂ (g) + H₂O
The bubbles are from CO₂ that is being developed from an acidic solution of CaCO₃
Answer:
Yes, it is possible. Let us consider an example of two solutions, that is, solution A having 20 percent mass RbCl (rubidium chloride) and solution B is having 15 percent by mass NaCl or sodium chloride.
It is found that solution A is having more concentration in comparison to solution B in terms of mass percent. The formula for mass percent is,
% by mass = mass of solute/mass of solution * 100
Now the formula for molality is,
Molality = weight of solute/molecular weight of solute * 1000/ weight of solvent in grams
Now molality of solution A is,
m = 20/121 * 1000/80 (molecular weight of RbCl is 121 grams per mole)
m = 2.07
Now the molality of solution B is,
m = 15/58.5 * 1000/85
m = 3.02
Therefore, in terms of molality, the solution B is having greater concentration (3.02) in comparison to solution A (2.07).
