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dusya [7]
3 years ago
7

An object has a mass of 5 kg and a velocity of 20 m/s. What is the momentum of the object?(1 point)

Physics
2 answers:
user100 [1]3 years ago
6 0

Answer:

100

Explanation:

its done beacuse the next person has already done it.

kotegsom [21]3 years ago
3 0

Answer:

option C is correct

Explanation:

given mass=5 kg  

velocity=20 m/s

momentum,P=m v

p=5*20=100 kg m/s

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A parachutist's falls to Earth is determined by two opposing forces. A gravitational force of 605 N acts on the parachutist. Aft
Juliette [100K]

Answer:

V_f=22.596\ m/sec

Explanation:

<u>Physics Dynamics </u>

The second Newton's Law, states the acceleration of a body will depend on the net force applied to it and its mass. If an object is left on free air the net force acting on it is the gravitational force. It will continue to fall with accelerated motion until that force is changed.

The formulas needed to compute the physics dynamics magnitudes are

F=ma

V_f=V_o+at

W=mg

The variables involved are: F=net force, m=mass, a=acceleration, V_f = final velocity, V_o = initial velocity, t = time, W = Weigh, g=9.8\ m/sec^2

At first, only the gravitational force of 605 N acts on the parachutist. That net force is due to the parachutist's weigh. We can know the mass

\displaystyle m=\frac{W}{g}=\frac{605N}{9.8m/sec^2}=61,735\ kg

If we assume the initial speed is 0, then

V_f=gt

All variables are assumed to be positive downwards. So, when t=3 sec

V_f=(9.8)(3)=29.4\ m/sec

Right then an air resistance force of 665 N appears. The new net force is

F=605N-665N=-60N

The new acceleration will be

\displaystyle m=\frac{F}{m}=\frac{-60N}{61,735\ kg}=-0.972\ m/sec^2

The acceleration is now negative since it goes upward. We are required to compute the speed after 10 sec (not clear if it's after this last event or it comes from the initial condition). We assume those 10 sec come from the very beginning of the jump, so t=7 sec

V_f=29.4\ m/s-0.972\ m/sec^2(7\ sec)=22.596\ m/sec

If it was t= 10\ sec

V_f=29.4\ m/s-0.972\ m/sec^2(10\ sec)=19.68\ m/sec

3 0
3 years ago
The Earth's Radius is 6.3710x106 m and mass is 5.9742x1024 kg. What is the acceleration due to gravity at Mount Everest (elevati
Shalnov [3]

Answer is

9.773m/s^2

-----------------------------------------------------------------------------

Given,

h=8848m

The value of sea level is 9.08m/s^2. So, Let g′ be the acceleration due to the gravity on Mount Everest.

g′=g(1 − 2h/h)

=9.8(1 - 6400000/17696)

=9.8(1 − 0.00276)

9.8×0.99724

=9.773m/s^2

Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s^2

-----------------------------------------------------------------------

hope this helps :)

3 0
3 years ago
What is a chemical energy
Papessa [141]

Chemical energy is the potential of a chemical substance to undergo a transformation through a chemical reaction to transform other chemical substances. Examples include batteries, food, gasoline, and etc.

8 0
3 years ago
When the drivers pass each other, the driver of the red car is to toss a package of contraband to the other driver. To catch the
Brrunno [24]

Answer:

D=387.28m

Explanation:

At the moment where the toss is made X_R = X_G, so we need both equations:

For the red car:

X_R=\frac{a_R*t^2}{2}   With initial speed of 0 and acceleration of 6.12m/s^2.

For the green car:

X_G=Xo + V_G*t   With V_G = 60km/h*\frac{1000m}{1km} * \frac{1h}{3600s} = 16.66m/s   and Xo = 200m

Since both positions will be the same:

\frac{a_R*t^2}{2}=Xo+V_G*t   Solving for t:

t1 = -5.8s  and   t1 =11.25s

Replacing t = 11.25 on either equation to find the displacement:

D = X_R = \frac{a_R*t^2}{2} = 387.28m

3 0
4 years ago
A point P is placed exactly between two charges, Q1 and Q2. If the electric field experienced by point P due to charge Q1 is 1.5
iren2701 [21]

<em>Answer:  D</em>

<em>Given data:</em>

The electric field due to charge q₁  is (E₁) = 1.5 × 10⁵ N/C

The electric field due to charge q₂ is (E₂) = 7.2 × 10⁵ N/C

Determine the net electric field at point P (Enet) = ?

electric field measured in Newtons/coulomb

<em>We know that,</em>

        The net electric field (Enet) is vector sum of E₁ and E₂ caused by the charge q₁ and q₂ respectively

             Enet = E₁ + E₂

                       = (1.5 × 10⁵)+ (7.2 × 10⁵)

                       = 8.7 × 10⁵ Newtons/coulomb

<em>The net electric field at point P is  8.7 × 10⁵ N/C</em>

4 0
4 years ago
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