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dusya [7]
3 years ago
7

An object has a mass of 5 kg and a velocity of 20 m/s. What is the momentum of the object?(1 point)

Physics
2 answers:
user100 [1]3 years ago
6 0

Answer:

100

Explanation:

its done beacuse the next person has already done it.

kotegsom [21]3 years ago
3 0

Answer:

option C is correct

Explanation:

given mass=5 kg  

velocity=20 m/s

momentum,P=m v

p=5*20=100 kg m/s

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If an object is thrown upward with an initial velocity of 128 ​ft/second, then its height after t seconds is given by the follow
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Answer:

The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.

Explanation:

Given that,

Initial velocity u= 128 ft/sec

Equation of height

h = 128t-32t^2....(I)

(a). We need to calculate the maximum height

Firstly we need to calculate the time

\dfrac{dh}{dt}=0

From equation (I)

\dfrac{dh}{dt}=128-64t

128-64t=0

t=\dfrac{128}{64}

t=2\ sec

Now, for maximum height

Put the value of t in equation (I)

h =128\times2-32\times4

h=128\ ft

(b). The number of seconds it takes the object to hit the ground.

We know that, when the object reaches ground the height becomes zero

128t-32t^2=0

t(128-32t)=0

128=32t

t=4\ sec

Hence, The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.

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What does it mean when a solution is saturated? -No more solute can dissolve in solvent. -The container is full. -The solvent ha
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3 years ago
A professional boxer hits his opponent with a 1035 N horizontal blow that lasts 0.175 s. The opponent's total body mass is 120 k
12345 [234]

Answer:

(a) vf = 1.51 m/s

(b) vf = 36.22 m/s

Explanation:

The rate of change of momentum is equal to the force:

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Ft = m(v_f-v_i)

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F = Force = 1035 N

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vi = initial speed = 0 m /s

vf = final speed = ?

(a)

m = mass of body = 120 kg

Therefore,

(1035\ N)(0.175\ s)=(120\ kg)(v_f - 0\ m/s)\\\\v_f = \frac{181.125\ Ns}{120\ kg} \\\\

<u>vf = 1.51 m/s</u>

<u></u>

(b)

m = mass of head = 5 kg

Therefore,

(1035\ N)(0.175\ s)=(5\ kg)(v_f - 0\ m/s)\\\\v_f = \frac{181.125\ Ns}{5\ kg} \\\\

<u>vf = 36.22 m/s</u>

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