Velocity = distance /time
acceleration = velocity / time
Required value of initial speed of the bullet be ( 4M/m)√(gL).
Given parameters:
Mass of the bullet =m.
Mass of the bob of the pendulum = M.
speed of the bullet before collision = v
Speed of the bullet after collision = v/2.
Length of the pendulum stiff rod = L.
Let speed transmitted to the pendulum be u.
Using principle of conservation of momentum:
mv = Mu + mv/2
⇒ Mu = mv/2
⇒ u = (m/M)v/2
We know that: to make the bob over the top of the trajectory without falling backward in its circular path, required speed be = √(4gL). [ where g = acceleration due to gravity]
To be minimum initial speed the bullet must have in order for the pendulum bob to just barely swing through a complete vertical circle:
u = √(4gL)
⇒ (m/M)v/2 = √(4gL)
⇒ v =( 4M/m)√(gL).
Hence, minimum required speed of the bullet be ( 4M/m)√(gL).
Learn more about speed here:
brainly.com/question/28224010
#SPJ1
Answer:

Explanation:
= Intensity of unpolarized light = 
= Angle of the filter = 
Intensity of light is given by

The intensity of light detected by the camera is 
Answer:
2.72 m/s
Explanation:
In 3 meters a person running 0.5 m/s accelerates 1.2 m/s².
It means,
Distance, s = 3 m
Initial velocity, u = 0.5 m/s
Acceleration, a = 1.2 m/s²
We need to find the final velocity of the person. Using equation of motion to find it as follows :

So, the final velocity of the person is 2.72 m/s.
It's a simple machine, consisting of a rigid bar that rotates about a fixed point which is known as "Fulcrum" (most important part), It <span>affects the effort, or force and do the amount of work
Hope this helps!</span>