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geniusboy [140]
4 years ago
12

What is the speed over the ground of an airplane flying at 100 km/h relative to the air caught in a 100-km/h right-angle crosswi

nd?
Physics
1 answer:
Rudiy274 years ago
4 0

Answer:

141.42 km/h

Explanation:

Since this is a 100km/h right angle crosswind, the speed vector with respect to the ground is the vector speed of the airplane with respect to air + the vector speed of the cross-wind with respect to the ground

<100,0> + <0,100> = <100,100>

This vector has a magnitude of

v = \sqrt{v_1^2 + v_2^2} = \sqrt{100^2 + 100^2} = \sqrt{10000 + 10000} = \sqrt{20000} = 141.42  km/h

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Calculate the net convective heat transfer loss rate from both vertical surfaces of the plate to the air. (hint: h values should
pychu [463]

Net convective heat transfer loss rate (gnet)

Gnet = 2h, A (Ts - T∞)

=2(4.51) (0.001) (25)

Gnet = 0.2250 W.

There are two types of convection: natural convection and forced convection. Natural convection is caused by differences in the density of liquids due to differences in temperature (eg "hot air rises"). Global atmospheric circulation and local weather phenomena (including wind) are due to convective heat transfer.

Newton's Law of Cooling is a widely used equation for calculating both forced and natural net convective. The formula for Newton's Law of Cooling is Q = h A ΔT. Equation parameters and their typical US and SI.

Learn more about Net convective at

brainly.com/question/9382711

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7 0
2 years ago
The electric field strength in the space between two closely spaced parallel disks is 1.0 105 N/C. This field is the result of t
balu736 [363]

Answer:

D=2.996\times 10^{-2} m

Explanation:

*Assume the parallel disks have equal diameters.

Given the electric strength as  1.0\times 10^5 N/C.  transferring 3.9\times 10^9 electrons, the disk's Area can be calculated using the formula:

E=\frac{\eta}{\epsilon_o}=\frac{Q}{A\epsilon_o}\\\\A=\frac{Q}{E\epsilon_o}\\\\=\frac{(3.9\times 10^9)\times (1.6\times10^{-19})}{(1.0\times 10^5 )\times (8.85\times10^{-12})}\\\\A=7.0508\times 10^{-4} \ m^2

#We now calculate the disks diameter:

A=\pi(D/2)^2\\\\2\sqrt{\frac{A}{\pi}}=D\\\\=2\sqrt{7.0508\times 10^{-4}/\pi}\\\\D=2.996\times 10^{-2} \ m

Hence, the diameter of the disks is D=2.996\times 10^{-2} m

8 0
4 years ago
What is power the quotient of?
andrey2020 [161]
Power is equal to work divided by time
4 0
3 years ago
Read 2 more answers
An object is suspended from the ceiling with two wires that make an angle of 40° with the ceiling. The weight of the body is 150
MaRussiya [10]
Refer to the diagram shown below.

Let T =  the tension in each wire.
For equilibrium,
2T cos(50°) = 150 N
1.2856T = 150
T = 116.677 N ≈ 117 N

Answer: 117 N

5 0
3 years ago
A uniform electric field is produced due to the charge distribution inside the closed cylindrical surface. (a) What type of char
DiKsa [7]

Answer with Explanation:

a. Option d is true.

a negatively charged plane parallel to the end faces of the cylinder

b. Radius of cylinder, r=0.66m

Magnitude of electric field, E=300 N/C

We have to find the net flux through the closed surface.

Net electric flux,\phi=-2 EA=-2E(\pi r^2)

\phi=-2\times 300\times (3.14\times (0.66)^2)

\phi=-820.67 Nm^2/C

c.

Net charge,Q=\epsilon_0\times \phi

Where

\epsilon_0=8.85\times 10^{-12}

Q=-820.67\times 8.85\times 10^{-12}

Q=-7.26\times 10^{-9} C

Q=-7.26nC

Where 1nC=10^{-9}C

7 0
3 years ago
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