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sergeinik [125]

4 years ago

10

Cot x sin x = cos x?

1 answer:

NeTakaya4 years ago

5 0

Answer:

cot(x) sin(x) = cos(x)

OK so what you are gonna do is first manipulate the left side of the equation

cot(x) sin(x)

So, you are gonna express with sin, cos

cos(x)/ sin(x) sin(x)

Then you will simplify cos(x)/ sin(x) sin(x) and get:

= cos (x)

So the equation cot(x) sin(x) = cos(x) is TRUE

(I hope this helps you! If it does please consider giving me the brainliest! It would really help me out and I would really appreciate it)

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What is the ratio of consonants to vowels in the english language?

LekaFEV [45]

There are 26 letters in the English Alphabet. 20 of them are Consonants and 5 of them are vowels. The letter Y is an exception that can fit into either category.

6 0

3 years ago

Read 2 more answers

The length of the hypotenuse of a right triangle is 7 feet, and the length of one leg is 4 feet. what is the length of the other

topjm [15]

The length of the other leg to the nearest tenth of a foot is 5.7 feet.

What is Pythagorean theorem?

A theorem in geometry: the square of the length of the hypotenuse of a right triangle equals the sum of the squares of the lengths of the other two sides.
The Pythagoras theorem equation is expressed as, $c^{2} = a^{2} + b^{2}$ , where 'c' = hypotenuse of the right triangle and 'a' and 'b' are the other two legs.

We can use the Pythagorean Theorem to find the length of the other leg

$a^{2} + b^{2} = c^{2}$

"a" and "c" represent the two legs of the triangle and "b" represents the perpendicular.

So,

$b^{2} = c^{2} - a^{2}$

= 7² - 4²

b = $\sqrt{49 - 16}$

$b = \sqrt{33}$ ⇒ 5.7 feet

Therefore, the length of the other leg to the nearest tenth of a foot is 5.7 feet.

Learn more about Pythagorean Theorem brainly.com/question/14605061

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4 0

2 years ago

2 x (6÷2 +8) -4 Help me

lana [24]

Answer:

22x-4

Step-by-step explanation:

2x(3+8)−4

Simplify 3+8 to 11.

2x×11−4

Simplify 2x times 11 to 22x.

22x−4

8 0

2 years ago

What is 8 raised to the fifth power?

ANEK [815]

Answer:

32768

Step-by-step explanation:

IM correct PLEASE give me brainliest i need one more for my rank

5 0

3 years ago

Read 2 more answers

A 200 gallon tank initially contains 100 gallons of water with 20 pounds of salt. A salt solution

luda_lava [24]

Set up a differential equation using rate of salt going in minus rate going out.

Rate = dS/dt = salt/gal* gal/min

Also the number of gallons in tank is increasing at (4-2) gal/min = 2 gal/min
The volume of tank at any given time = 100+2t

Differential Equation:
$\frac{dS}{dt} = (\frac{1}{4})(4) - (\frac{S}{100+2t}) (2)
 \\ \\ \frac{dS}{dt} = 1 - \frac{S}{t + 50} \\ \\ \frac{dS}{dt} + (\frac{1}{t+50}) S = 1$

Use integrating factor of t+50
$[S(t+50)]' = t+50$

Integrate both sides
$S(t+50) = \frac{t^2}{2} + 50t + c$
Solve for constant c given S(0) = 20
c = 1000

Tank is full at 200 gallons when t =50
100+2t = 200 ---> t = 50

S(50) = 47.5

Final Answer: There are 47.5 pounds of salt

4 0

3 years ago