Question

If you can explain your answer that’d be great!! Thank you!

Answer 1

Answer:

$A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}$

Step-by-step explanation:

This half life exponential decay equation goes by the formula:

$A(t)=A_{0}e^{kt}$

Where

$k=\frac{ln(\frac{1}{2})}{Half-Life}$

Since half life is given as 22, we plug that into "Half-Life" in the formula for k and then plug in the formula for k into the exponential decay formula:

So,

$k=\frac{ln(\frac{1}{2})}{Half-Life}\\k=\frac{ln(\frac{1}{2})}{22}$

Now

$A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}$

third choice is correct.