Question

A taxi driver had 50 fares to and from the airport last Monday. The price for a ride to the airport is $10, and the price for a ride from airport is $5. The driver collected a total of $375 for the day.

Answer 1

Answer:

Number of Fares to airport is 25 and number of fares from airport is 25.

Step-by-step explanation:

Given:

Total Number of fares =50

Let number of fares to airport be x.

Let number of fares from airport be y.

hence the equation can be framed as;

$x+y=50 \ \ \ \ equation \ 1$

Also Given

Total Money Collected = $375

Cost to airport = $10

Cost from Airport = $5

Total Money Collect is equal to Cost to airport multiplied by number of Fares to airport plus Cost from airport multiplied by number of Fare from airport.

$10x+5y=375$

Dividing by 5 on both side we get;

$2x+y = 75 \ \ \ \ equation \ 2$

Now Subtracting equation 1 from 2 we get;

$(2x+y)-(x+y)=75-50\\2x+y-x-y=25\\x=25$

Substituting the value of x in equation 1 we get;

$x+y=50\\25+y=50\\y=50-25\\y=25$

Hence Number of Fares to airport is 25 and number of fares from airport is 25.