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3 years ago

5

A taxi driver had 50 fares to and from the airport last Monday. The price for a ride to the airport is $10, and the price for a

ride from airport is $5. The driver collected a total of $375 for the day.

1 answer:

Rina8888 [55]3 years ago

5 0

Answer:

Number of Fares to airport is 25 and number of fares from airport is 25.

Step-by-step explanation:

Given:

Total Number of fares =50

Let number of fares to airport be x.

Let number of fares from airport be y.

hence the equation can be framed as;

$x+y=50 \ \ \ \ equation \ 1$

Also Given

Total Money Collected = $375

Cost to airport = $10

Cost from Airport = $5

Total Money Collect is equal to Cost to airport multiplied by number of Fares to airport plus Cost from airport multiplied by number of Fare from airport.

$10x+5y=375$

Dividing by 5 on both side we get;

$2x+y = 75 \ \ \ \ equation \ 2$

Now Subtracting equation 1 from 2 we get;

$(2x+y)-(x+y)=75-50\\2x+y-x-y=25\\x=25$

Substituting the value of x in equation 1 we get;

$x+y=50\\25+y=50\\y=50-25\\y=25$

Hence Number of Fares to airport is 25 and number of fares from airport is 25.

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3 years ago

Find the smallest number to be added to 11650 so that the sum will be a perfect square

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14

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3 years ago

Elena-2011 [213]

Answer:15

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2 years ago

Drag numbers to the table so it shows a proportional relationship between x and y.

Marat540 [252]

Using the proportional relationship equation, the missing values are:

Third row: x = 6 and y = 9

Fourth row: x = 15

<h3>What is a Proportional Relationship?</h3>

A proportional relationship can be described as a relationship between two variables, x and y, that have equivalent ratios. In order words, one variable always equals a constant when multiplied by the other variable.

The constant is called the constant of proportionality which can be represented as k.

Thus, k = y/x.

A proportional relationship between x and y can be represented with the equation, y = kx, where k is the constant of proportionality.

Using the pairs given in the table, (3, 4.5), find the constant of proportionality, k:

k = y/x = 4.5/3

k = 1.5

The equation that models the proportional relationship of the values in the table would be: y = 1.5x.

Use the equation to find the rest of the missing values.

Third row:

If x = 6 and y = 9, then,

k = y/x = 9/6 = 1.5

The missing values for the third row would be: x = 6 and y = 9

Fourth row: Substitute y = 2.5 into y = 1.5x to find x

22.5 = 1.5x

22.5/1.5 = x

15 = x

x = 15

Missing value in the fourth row will be: x = 15.

Learn more about proportional relationship on:

brainly.com/question/15618632

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2 years ago

Help please<3 for all questions with solutions plz

antiseptic1488 [7]

Answer:

a) $h = -\frac{7}{4}$ , b) $h = f\,\circ\,g (-5) = \frac{3}{2}$ , c) $h = g\,\circ\,f (-2) = \frac{3}{8}$

Step-by-step explanation:

We proceed to solve each exercise below:

a) $f(-2) +3\cdot g(0)$

$h = \frac{2\cdot (-2)}{3\cdot (-2)+5}+3\cdot \left(\frac{3}{0+4} \right)$

$h = \frac{-4}{-6+5} +3\cdot \left(\frac{3}{4} \right)$

$h = -4+\frac{9}{4}$

$h = \frac{-16+9}{4}$

$h = -\frac{7}{4}$

b) $h = f\,\circ \,g (-5)$

$h = f\,\circ\,g (x) = \frac{\frac{6}{x+4} }{\frac{9}{x+4}+5 }$

$h = f\,\circ\,g (x)= \frac{\frac{6}{x+4} }{\frac{9+5\cdot (x+4)}{x+4} }$

$h = f\,\circ\,g (x) = \frac{6}{29+5\cdot x}$

$h = f\,\circ\,g (-5) = \frac{6}{29+5\cdot (-5)}$

$h = f\,\circ\,g (-5) = \frac{3}{2}$

c) $h = g\,\circ\,f(-2)$

$h = g\,\circ \, f (x) = \frac{3}{\frac{2\cdot x}{3\cdot x + 5} + 4 }$

$h = g\,\circ\,f (x) = \frac{3}{\frac{2\cdot x +4\cdot (3\cdot x +5)}{3\cdot x +5 } }$

$h = g\,\circ \,f (x) = \frac{3\cdot (3\cdot x +5)}{2\cdot x +12\cdot x +20}$

$h = g\,\circ\,f(x) = \frac{9\cdot x +15}{14\cdot x +20}$

$h = g\,\circ\,f(-2) = \frac{9\cdot (-2)+15}{14\cdot (-2)+20}$

$h = g\,\circ\,f (-2) = \frac{-3}{-8}$

$h = g\,\circ\,f (-2) = \frac{3}{8}$

6 0

3 years ago