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ankoles [38]
3 years ago
13

Cost per year Graduation Rate Loan Default

Mathematics
1 answer:
zmey [24]3 years ago
4 0

Answer:

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Which is a solution for the equation 3x + 13 = 73?
sweet [91]

Answer:

x=20

Step-by-step explanation:

73-13=60

60÷3=20

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Please help asap <br> Algebra 2
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2144 \: is \: the \: answer

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PLZ HELP WILL GIVE BRAINLIEST 50+25 POINTS!!!<br><br>Graph the following piecewise function.
Luda [366]

We need to graph the given piecewise function.

To graph any piecewise function we do that into parts

Let's graph upper part first which is

f(x)=x^2+2

restriction for that is -5 \leq x < 3

that means we are free to pick any number for x that is between -5 and 3, including 3.

So we will find few points by plugging random numbers between -5 and 3.

Let's use x=-5, we get:

f(-5)=(-5)^2+2=25+2=27

so first point is (-5,27).

similarly we can find other points like (0,2), (2,6), (-1,3) etc.

Now we join those points by a curved line.

-5 \leq x means we use a close circle at -5

x<3 means use open circle at 3


------------

Repeat same process for 2nd part f(x)=x-4

choose any number between 3 and 7 like x=3, 4 etc

so we get points (3,-1), (4,0) etc

Now graph them

So the final graph will look like:


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A single die is rolled. Find the probability of getting an odd number or a number less<br> than 5.
Eddi Din [679]

Answer:

Answer:Rolling a odd number is 1/5 and rolling a number less than five is 3/5

Step-by-step explanation:

3 0
3 years ago
It has been said that newspapers are disappearing, replaced by various electronic media. In 2004, newspaper circulation (the num
shutvik [7]

Answer:

A. y=-1.2x+59

B. 42.2 million

Step-by-step explanation:

Part A:

Given:

Newspapers circulated in year 2004, y_{1}=59\textrm{ million}

Newspapers circulated in year 2014, y_{2}=47\textrm{ million}

Let the time x start at the year 2004. So, x_{1}=0

For the year 2014, x_{2}=2014-2004=10

Therefore, linear relationship between newspapers circulated and time passed since 2004 is given as:

y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1})\\y-59=\frac{47-59}{10-0}(x-0)\\y-59=-\frac{12}{10}x\\y=-1.2x+59

Therefore, the equation describing the relationship is: y=-1.2x+59

Part B:

For the year 2018, x=2018-2004=14

Plug in 14 for x in the above equation and solve for y. This gives,

y=-1.2(14)+59\\y=-16.8+59\\y=42.2

Therefore, in the year 2018, the newspaper circulation will be 42.2 million.

8 0
3 years ago
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