Answer:
Consider the following calculation
Explanation:
Yield to maturity is not given here. So we assume that Yield to maturity is 10%.
Present value of interest payment :
PV = A*PVIFA (n= 40,i =10%)
= 170*9.7791
= 1662.45
Present value of principal payment at maturity
PV = FV*PVIF (n= 40,i =10%)
= 1000 * .0221
= 22.10
Current price of bond = 1662.45+22.10
= $ 1684.55
Answer:
$70,875
Explanation:
By definition, a flexible budget is when a budget has been adjusted or flexed to accommodate the changes in the level of activity.
If the company wanted to create a flexible budget for 9,000 units, then the value that would be recorded for variable costs will be:
Indirect materials, $22,000/8000*9000 = 24,750;
Indirect labor, $25,000/8000*9000 = 28,125 ;
Utilities, $12,000/8000*9000 = 13,500;
Supervision, $4,000/8000*9000=4,500
Total of variable costs = ........................70,875
Answer:
- <em>As explained below, given that the score of the person is among the 0.03125 fraction of the best applicants, </em><u><em>he can count on getting one of the jobs.</em></u>
<em></em>
Explanation:
The hint is to use <em>Chebyshev’s Theorem.</em>
Chebyshev’s Theorem applies to any data set, even if it is not bell-shaped.
Chebyshev’s Theorem states that at least 1−1/k² of the data lie within k standard deviations of the mean.
For this sample you have:
- mean: 60
- standard deviation: 6
- score: 84
The number of standard deviations that 84 is from the mean is:
- k = (score - mean) / standar deviation
- k = (84 - 60) / 6 = 24 / 6 = 4
Thus, the score of the person is 4 standard deviations above the mean.
How good is that?
Chebyshev’s Theorem states that at least 1−1/k² of the data lie within k standard deviations of the mean. For k = 4, that is:
- 1 - 1/4² = 1 - 1/16 = 0.9375
- That means that half of 1 - 0.9375 are above k = 4: 0.03125
- Then, 1 - 0.03125 are below k = 4: 0.96875
Since there are 70 positions and 1,000 aplicants, 70/1,000 = 0.07. The compnay should select the best 0.07 of the applicants.
Given that the score of the person is among the 0.03125 upper fraction of the applicants, this person can count of geting one of the jobs.
I believe the correct answer is C!
