Answer:
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
Step-by-step explanation:
given that acceleration vector is a funciton of time and at time t
v(t) can be obtained by integrating a(t)
v(t) = 
Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.
The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)
Position vector can be obtained by integrating v(t)
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
Answer:
x=−18.849556r2+v/6.283185r
Step-by-step explanation:
Step 1: Flip the equation.
18.849556r2+6.283185rx=v
Step 2: Add -18.849556r^2 to both sides.
18.849556r2+6.283185rx+−18.849556r2=v+−18.849556r2
0r 2+6.283185rx=−18.849556r2+v
Step 3: Divide both sides by 6.283185r. 0r2+6.283185rx/
6.283185r = −18.849556r2+v/6.283185r
x=−18.849556r2+v/6.283185r
-34.44 +49.44 = 15
The highest recorded temperature was 15 degrees.
Answer:
20 girls
Step-by-step explanation:
3:5; this means that if there were 8 students, 3 would be girls and 5would be girls. Using this info we can multiply the ratio by a umber that will turn the total amount of students to 32.
4(3:5)=12:20
12+20=32
12 boys and 20 girls in a class of 32 students.
