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Sav [38]
3 years ago
13

4(2x + 2) = 88 how do u solve this

Mathematics
2 answers:
almond37 [142]3 years ago
7 0

Answer: X = 10

Step-by-step explanation:

4(2x + 2) = 88

Multiply 4(2x) and 4(2)

You will get 8x + 8 = 88

Subtract 8 from both sides

8x = 88

Divide 8

X = 10

Vikki [24]3 years ago
5 0

Answer: x= 10

Step-by-step explanation: distribute: 4(2x+2)=88

8x+8=88

Subtract 8 from both sides

8x= 80

Divide both sides by 8

X=10

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Graph a triangle (STU) and reflect it over the y-axis to create triangle ST'U'.
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The x-coordinates of \triangle S'T'U' will be the negation of the x-coordinates of \triangle STU

The line segment from S to the y-axis equals the line segment from S' to the y-axis. Similarly, the line segment from T to the y-axis equals the line segment from T' to the y-axis

See attachment for \triangle STU and \triangle S'T'U'

In order to solve this question, I will make the following assumptions.

Assume that the coordinates of \triangle STU are

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Refer to attachment for illustrations

<u>(1) Reflect </u>\triangle STU<u> over y-axis and describe the transformation</u>

To reflect \triangle STU across the y-axis, the following rule must be followed

(x,y) \to (-x,y)

This means that:

S = (4,5) \to S' = (-4,5)

T = (5,9) \to T' = (-5,9)

U=(3,8) \to U'=(-3,8)

<u>The description of the </u><u>transformation </u><u>is as follows:</u>

Notice that the signs of the x-coordinates \triangle STU and \triangle S'T'U' of both triangles are different.

In other words, if the x-coordinate of one is positive, then the other will have a negative x-coordinate; and vice versa.

<u>(2) Compare the segments and the line of reflection</u>

To reflect across the y-axis means that the reflecting line is the y-axis, itself.

The distance between a point to the y-axis is the absolute value of the x-coordinate.

So, the distance between S and the y-axis is:

S = |4| = 4

The distance between S' and the y-axis is:

S' = |-4| = 4

We can conclude that the two line segments are equal.

This is the same for other point T and T' because of the formula used above.

<u>From T and T' to the y-axis is:</u>

T =|5| =5

T' =|-5| =5

Read more at:

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