Answer:
Empirical formula is KHO₃C.
Explanation:
Given data:
Percentage of potassium = 39.0%
Percentage of hydrogen = 1.01%
Percentage of carbon = 12.0%
Percentage of oxygen = 47.9%
Empirical formula = ?
Solution:
Number of gram atoms of K = 39.0/ 39 = 1
Number of gram atoms of H = 1.01 / 1.01 = 1
Number of gram atoms of O = 47.9 / 16 = 3
Number of gram atoms of C = 12 / 12 = 1
Atomic ratio:
K : H : O : C
1/1 : 1/1 : 3/1 ; 1/1
1 : 1 : 3 : 1
K : H : O :C = 1: 1 : 3 : 1
Empirical formula is KHO₃C.
Answer:
It's B !
Explanation:
Formulas. The molecular formula for glucose is C6H12O6. This means that there are 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms bonded together to make one molecule of glucose.
Hope this helps!!
(1,2 because c is already on the other side so you have to reverse it
Acid+alkali->salt+water which is neutralization
