Question

In an acid-base neutralization reaction 38.74 ml of 0.500 m potassium hydroxide reacts with 50.00 ml of sulfuric acid solution. What is the concentration of the h2so4 solution?

Answer 1

Answer:

0.2 M.

Explanation:

• For the acid-base neutralization, we have the role:

The no. of millimoles of acid is equal to that of the base at the neutralization.

∴ (XMV) KOH = (XMV) H₂SO₄.

X is the no. of reproducible H⁺ (for acid) or OH⁻ (for base),

M is the molarity.

V is the volume.

• For KOH:

X = 1, M = 0.5 M, V = 38.74 mL.

• For H₂SO₄:

X = 2, M = ??? M, V = 50.0 mL.

∴ M of H₂SO₄ = (XMV) KOH/(XV) H₂SO₄ = (1)(0.5 M)(38.74 mL)/(2)(50.0 mL) = 0.1937 M ≅ 0.2 M.