Answer:
116.4 g of SiCl4
Explanation:
SiCl4(l) +2H2O(l) -------> SiO2 (s) + 4HCl(aq)
Given this balanced reaction equation which will serve as a guide for our work, we can now look at the stoichiometry of the reaction.
Number of moles of HCl needed = mass of HCl/ molar mass of HCl
Molar mass of HCl= 36.46 g/mol
Number of moles of HCl= 100/36.46 g/mol= 2.74 moles
From the balanced reaction equation;
1 mole of SiCl4 yields 4 moles of HCl
x moles of SiCl4 will yield 2.74 moles of HCl
x= 2.74/4 = 0.685 moles of SiCl4
Therefore mass of SiCl4= number of moles of SiCl4 × molar mass of SiCl4
Mass of SiCl4= 0.685× 169.9 g/mol = 116.4 g of SiCl4
