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3 years ago

Definition: This is the difference between the estimated value and the true value.

Mathematics

2 answers:

Anuta_ua [19.1K]3 years ago

7 0

Answer:

its called an error

Step-by-step explanation:

rodikova [14]3 years ago

6 0

Answer:

Estimated value is an educated guess. A true value is the correct answer.

Step-by-step explanation:

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Please help lol and thank u

Aleksandr-060686 [28]

Step-by-step explanation:

The picture shows us that the shape is a square.

To find the area of a square you would use the formula s^2

s= 8ft

8ft^2 = 64ft^2

with area you would need to use the unit ft^2

I hope this helps!!!

5 0

2 years ago

Read 2 more answers

What is 2/3, 66%, and 0.67 from greatest to least

Effectus [21]

66%, then 2/3, and lastly 0.67. 2/3 is repeating so it is more then 66% but less than 0.67

4 0

3 years ago

Read 2 more answers

.<br> g. When f(x) = 0, what is the value of x.

Hatshy [7]

Answer: x=0

Step-by-step explanation:

8 0

3 years ago

The equation of the tangent plane to the ellipsoid x2/a2 + y2/b2 + z2/c2 = 1 at the point (x0, y0, z0) can be written as xx0 a2

svetlana [45]

Answer:

The equation of tangent plane to the hyperboloid

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=1$ .

Step-by-step explanation:

Given

The equation of ellipsoid

$\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1$

The equation of tangent plane at the point $\left(x_0,y_0,z_0\right)$

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}+\frac{zz_0}{c^2}=1$ ( Given)

The equation of hyperboloid

$\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}{c^2}=1$

F(x,y,z)= $\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}[c^2}$

$F_x=\frac{2x}{a^2},F_y=\frac{2y}{b^2},F_z=-\frac{2z}{c^2}$

$(F_x,F_y,F_z)(x_0,y_0,z_0)=\left(\frac{2x_0}{a^2},\frac{2y_0}{b^2},-\frac{2z_0}{c^2}\right)$

The equation of tangent plane at point $\left(x_0,y_0,z_0\right)$

$\frac{2x_0}{a^2}(x-x_0)+\frac{2y_0}{b^2}(y-y_0)-\farc{2z_0}{c^2}(z-z_0)=0$

The equation of tangent plane to the hyperboloid

$\frac{2xx_0}{a^2}+\frac{2yy_0}{b^2}-\frac{2zz_0}{c^2}-2\left(\frac{x_0^2}{a^2}+\frac{y_0^2}{b^2}-\frac{z_0^2}{c^2}\right)=0$

The equation of tangent plane

$2\left(\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}\right)=2$

Hence, the required equation of tangent plane to the hyperboloid

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=0$

7 0

3 years ago

(7, 5) and (-3, 4) written in slope intercept form

Rom4ik [11]

Answer:

y = x/10 + 43/10

Step-by-step explanation:

y - y1/ x - x1 = y2 - y1/ x2 - x1

y - 4/ x +3 = 5 - 4/7 + 3

y - 4 / x + 3 = 1/10

10(y - 4) = x + 3

10y - 40 = x + 3

10y = x + 43

y = x/10 + 43/10

8 0

3 years ago