Explanation:
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Answer: But-2-enoic acid has
11 Sigma Bonds and
2 Pi Bonds.
Explanation: The sigma bonds which are formed due to head to head overlap of partally filled orbitals are shown in
red color, while Pi bonds which are formed after the formation of sigma bond by overlap of orbitals perpendicular to the sigma bond are shown in
blue color.
Answer:
C6H14O3F
Explanation:
The first step is to divide each compound by its molecular weight
Carbon
= 39.10/12
= 3.258
Hydrogen
= 7.67/1
= 7.67
Oxygen
= 26.11/16
= 1.63
Phosphorous
= 16.82/31
= 0.542
Flourine
= 10.30/19
= 0.542
The next step is to divide by the lowes value
3.258/0.542
= 6 mol of C
7.67/0.542
= 14 mol of H
1.63/0.542
= 3 mol of O
0.542/0.542
= 1 mol of P
0.542/0.542
= 1 mol of F
Hence the molecular formula is C6H14O3F
The anticodons corresponding to the codons on the mRNA (from part A) is 5' CGA - AAA - GUU 3'.
<h3>What are anticodons?</h3>
Anticodons are nucleotide sequences on tRNA molecules that are complementary to the codons found on mRNA molecules.
The anticodons on tRNA molecules determine the amino acid that is carried by the tRNA.
Just like codons, anticodons occur in triplets of nucleotide sequences.
Considering the codons on the mRNA molecule:
3’ GCT | TTT | CAA | AAA ’5
The complementary anticodon will be:
5' CGA - AAA - GUU 3'
Learn more about anticodons at:brainly.com/question/28067314
#SPJ1
Answer:
Explanation has been given below.
Explanation:
- Chloroform has three polar C-Cl bonds. Methylene chloride has two polar C-Cl bonds. So it is expected that chloroform should be more polar and posses higher dipole moment than methylene chloride.
- Two factors are liable for the opposite trend observed in dipole moments of methylene chloride and chloroform.
- First one is the number of hyperconjugative hydrogen atoms present in a molecule. Hyperconjugation occurs with vacant d-orbital of Cl atom. Hyperconjugation amplifies charge separation in a molecule resulting higher dipole moment.
- Methylene chloride has two hyperconjugative hydrogen atoms and chloroform has one hyperconjugative hydrogen atom.Therefore methylene chloride should have higher charge separation as compared to chloroform.
- Second one is induction of opposite polarity in a C-Cl bond by another C-Cl bond in a molecule. Higher the opposite induction of polarity, lower the charge separation in a molecule and hence lower the dipole moment of a molecule.
- Chloroform has three C-Cl bonds and methylene chloride has two C-Cl bonds. Therefore opposite induction is higher for chloroform resulting it's lower dipole moment.