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alexgriva [62]
3 years ago
13

What are the 4 major macromolecules

Chemistry
1 answer:
ANEK [815]3 years ago
8 0
Carbohydrates
Lipids
Protein
Nucleic acids
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Why is it important to communicate the results of an investigation?
denis-greek [22]

Answer:

Communicating Results

This is a very important step because it allows other scientists to try to repeat the investigation and see if they can produce the same results. When scientists communicate their results, they should describe their methods and point out any possible problems with the investigation.

Hoped I helped

7 0
4 years ago
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Please help me please please :(
Annette [7]

Answer:

B. and A.

Explanation:

May I have the Brainlliest award?

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g The following equation is given for the dissociation of the complex ion Ag(NH3) 2. The dissociation constant, Kd, is the equil
Sveta_85 [38]

Answer:

Kd = [Ag⁺] × [NH₃]² / [Ag(NH₃)₂⁺]

Explanation:

Let's consider the dissociation reaction of the complex ion Ag(NH₃)₂⁺.

Ag(NH₃)₂⁺(aq) ⇄ Ag⁺(aq) + 2 NH₃(aq)

The dissociation constant, Kd, is the equilibrium constant for the dissociation of the complex ion, that is, it is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.

The dissociation constant for this reaction is:

Kd = [Ag⁺] × [NH₃]² / [Ag(NH₃)₂⁺]

8 0
3 years ago
What type of blood goes to the right side of the heart​
Anastasy [175]

Deoxygenated Blood enters and leaves the right side of the heart then Oxygenated blood enters and leaves the left side of the heart

5 0
3 years ago
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A sample of paper from an ancient scroll was found to contain 39.5% 14C content as compared to a present-day sample. The t1/2 fo
nirvana33 [79]

Answer

7665 years

Procedure

Let N₀ be the amount of carbon-14 present in a living organism. According to the radioactive decay law, the number of carbon-14 atoms, N, left in a dead tissue sample after a certain time, t, is given by the exponential equation:

N = N₀e^(-λt)

where λ is the decay constant which is related to half-life (T1/2) by the equation:

\lambda=\frac{ln(2)}{t_{\frac{1}{2}}}

Here, ln(2) is the natural logarithm of 2.

The percent of carbon-14 remaining after time t is given by N/N₀.

Using the first equation, we can determine λt.

The half-life of carbon-14 is 5,720 years, thus, we can calculate λ using the second equation, and then find t.

\lambda=\frac{ln(2)}{5720}=1.211\times10^{-4}

Solving the second equation for t, and using the λ we have just calculated we will have

t= 7665 years

3 0
1 year ago
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