Half life of the reaction is :-101.9 min
a→b
25% reacted means 75% remains
t=42 min
Rate constant
k=(2.303/t)(log a/a-x)
k=(2.303/42)(log 100/100-25 )
k=(0.054) (log 100/75)
k=(0.054)(0.1249)
k=0.0068per min
half life
t1/2=(0.693/k)
=(0.693/0.0068)
=101.9 min
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Answer:
Number of moles = 0.51 mol
Explanation:
Given data:
Mass of CO₂ = 22.4 g
Number of moles = ?
Solution:
Number of moles of CO₂:
Number of moles = mass/molar mass
Molar mass of CO₂ = 44 g/mol
by putting values,
Number of moles = 22.4 g/ 44 g/mol
Number of moles = 0.51 mol
Answer:
Explanation:
There are three fundamentally known states of matter save for plasma and the Bose-Einstein condensate. These states of matter are solid, liquid and gas.
We can classify nearly all matter into these discrete categories based on certain lucid characteristics they exhibit.
- Solids have definite shape and volume and they exhibit by the far the most remarkable internal ordering. Their molecules are attached by strong internal forces.
- Liquids do not have a definite shape but takes the shape of the contains that hold them. They are not random and have internal cohesion among them.
- Gases are random particles and highly varied. They move haphazardly and have no definite shape and volume.
Answer:
A. 4.5 mol Mg(OH)₂
B. 6 mol NaOH
Explanation:
Let's consider the following balanced equation.
Mg(NO₃)₂ + 2 NaOH ⇒ Mg(OH)₂ + 2 NaNO₃
PART A
The molar ratio of NaOH to Mg(OH)₂ is 2:1. The moles of Mg(OH)₂ produced from 9 moles of NaOH are:
9 mol NaOH × 1 mol Mg(OH)₂/2 mol NaOH = 4.5 mol Mg(OH)₂
PART B
The molar ratio of NaOH to NaNO₃ is 2:2. The moles of NaOH needed to produce 6 moles of NaNO₃ are:
6 mol NaNO₃ × 2 mol NaOH/2 mol NaNO₃ = 6 mol NaOH
Atom can never be divided into smaller particles is the answer was disproved
