add all the number and find the average then subtract the mass defect and then you will get your answer
Considering the definition of pOH and strong base, the pOH of the aqueous solution is 1.14
The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution and indicates the concentration of ion hydroxide (OH-).
pOH is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
On the other hand, a strong base is that base that in an aqueous solution completely dissociates between the cation and OH-.
LiOH is a strong base, so the concentration of the hydroxide will be equal to the concentration of OH-. This is:
[LiOH]= [OH-]= 0.073 M
Replacing in the definition of pOH:
pOH= -log (0.073 M)
<u><em>pOH= 1.14 </em></u>
In summary, the pOH of the aqueous solution is 1.14
Learn more:
The electron dot diagram for the oxygen atom shows six electrons around the symbol of the atom.
<h3>What is the electron dot diagram?</h3>
The electron dot diagram is the diagram of atoms of elements showing only the valence electrons present in the atom represented with dots.
The electron dot diagram for the oxygen atom is drawn as follows:
- The number of valence electrons in oxygen atom is determined; valence electrons = 6
- The symbol for the oxygen atom is written
- The valence electrons are shown as dots around the symbol of the element.
In conclusion, the electron dot diagram uses dots around the symbol of an atom to show the valence electrons in the atom.
Learn more about electron dot diagram at: brainly.com/question/5835591
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1) Dalton stated that atom is matter that can not be divided, but it is proved that the atom can be divided into subatomic particles (electrons, protons and neutrons).
2) He stated that atoms of one element can not be changed into atoms of other elements, but now that is possible by nuclear reactions.
Today we still use his postulate: Atoms combine in the ratio of small whole numbers to form stable compounds, for example H₂O.
Answer:
The half-cells separate the oxidation half-reaction from the reduction half-reaction and make it possible for current to flow through an external wire.
Explanation:
