density is mass/volume so we do
.115/.000265
433.962 g/mL
Answer:
There are
4.517
⋅
10
23
atoms of Zn in 0.750 mols of Zn.
Explanation:
Since we know that there are
6.022
⋅
10
23
atoms in every mole of a substance (Avogadro's Number), there are
6.022
E
23
⋅
0.750
atoms of Zn in 0.750 mols of Zn.
Explanation:
The given data is as follows.
= 10 mM =
M
= 750 ml,
= 5 ml
= ?
Therefore, calculate the molarity of given NaCl stock as follows.


= 1.5 M
Thus, we can conclude that molarity of given NaCl stock is 1.5 M.
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