Question

the normal boiling point of ethanol is 78.3 and its molar heat of vaporization is 393. Calculate the vapor pressure of ethanol at 45.0 C

Answer 1

0.12 atm vapor pressure of ethanol at 45.0 C.

What is vapor pressure in science definition?

• Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature.
• The temperature at which the vapour pressure at the surface of a liquid becomes equal to the pressure exerted by the surroundings is called the boiling point of the liquid.

We will use the Clausius-Clapeyron equation,

ln(P2/P1) = dHvap/R[1/T1-1/T2]

where,

P1 = unknown

P2 = 1 atm

T1 = 30 oC = 30 + 273 = 303 K

T2 = 78.3 oC = 78.3 + 273 = 351.3 K

dHvap = 39.3 kJ/mol = 39300 J/mol

R = 8.314 J/K.mol

Feed values,

ln(1/P1) = 39300/8.314[1/303 - 1/351.3]

P1 = 0.12 atm

thus, the vapor pressure at 30° C is 0.12 atm.

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