Instantaneous rate of change = S'(r) = 8πr
S'(8) = 8π(8) = 64π
Therefore, the instantaneoud rate of change of the <span>surface area with respect to the radius r at r = 8</span> is 64π
Answer:
t =12 m
Step-by-step explanation:
We can use similar triangles and proportions to solve this problem.
Put the smaller triangle on top and the larger triangle on bottom
12 9
------ = -------
16 t
Solve by using cross products
12 t = 9*16
12 t =144
Divide by 12
12t/12 = 144/12
t = 12
Answer:
Please check the explanation.
Step-by-step explanation:
Given
a)
f(x) + g(x) = (2x - 1) + (2 - x)
= 2x -1 + 2 - x
= x + 1
b)
f(x) - g(x) = (2x - 1) - (2 - x)
= 2x - 1 - 2 + x
= 3x - 3
c)
g(-5) - f(-5)
Putting x = -5 in g(x) = 2 - x
g(x) = 2 - x
g(-5) = 2 - (-5) = 2+5 = 7
Putting x = -5 in f(x) = 2x - 1
f(x) = 2x - 1
f(-5) = 2(-5) - 1
= -10 - 1
= -11
Thus,
g(-5) - f(-5) = 7 - (-11) = 7+11 = 18
d)
f(x).g(x) = (2x - 1) (2 - x) = -2x² + 5x - 2
e)
f(g(x)) = f(2-x)
= 2(2-x)-1
= 4-2x-1
= 3-2x
If you put them into to proportion
156/400 and then put a variable for the unknown x/1200
1200 divided by 400 = 3
156 times 3 = 468
468 order salad out of 1200
Answer:
change the equation into one variable.
2 y equals 10 + x
y equals 5 + x by 2
now put that into the second equation
-3x + b parentheses 5 + x / 2 equals 11
-3x+b(5+ x/2)
-3x + b5 + bx/2 = 11
