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3 years ago

What is the function of the uterus during embryo development?

Physics

1 answer:

nalin [4]3 years ago

3 0

Answer:

The uterus plays a significant part in the pregnancy, menstruation, zygote implantation, conception, labor, and delivery of the baby along with other essential reproductive system organs.

Explanation:

The uterus is a female reproductive organ that is pare shaped and situated between the urinary bladder and the rectum ins the pelvis. The placenta develops links with the uterine blood vessels that provide the embryo with nutrition through an umbilical cord. When this happens, the uterus delivers signals to the brain to adjust the secretion of the hormone such that releases of more eggs (i.e. ovulation) are halted and the menstrual cycle momentarily stops, thereby verifying the pregnancy. In pregnancy the uterus provides the space and an adequate atmosphere for the fetus to develop safely, it provides feedback to the brain which regulates hormones release. The uterus forms a link between the mother and the baby through the placenta and umbilical cord not only to provide the requisite nutrients and oxygen but also to extract the waste products and purify the blood of the fetus before the fetal organs take over.

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Question 4 of 11

givi [52]

Answer: C

C. Place plastic around the metal wires, because electric charges

hardly move in plastic.

4 0

3 years ago

Scenario 2: Use the following information to answer questions 3 and 4:

NemiM [27]

Answer:

A. 52 min

.A. 47 watts

Explanation:

Given that;

jim weighs 75 kg

and he walks 3.3 mph; the objective here is to determine how long must he walk to expend 300 kcal.

Using the following relation to determine the amount of calories burned per minute while walking; we have:

$\dfrac{MET*weight (kg)*3.5}{200}$

here;

MET = energy cost of a physical activity for a period of time

Obtaining the data for walking with a speed of 3.3 mph From the standard chart for MET, At 3.3 mph; we have our desired value to be 4.3

However;

the calories burned in a minute = $\dfrac{4.3*75 (kg)*3.5}{200}$

= 5.644

Therefore, for walking for 52 mins; Jim burns approximately 293.475 kcal which is nearest to 300 kcal.

Given that:

mass m = 75 kg

intensity = 6 kcal/min

The eg ergometer work rate = ??

Applying the formula:

$V_O_2 ( intensity ) = ( \dfrac{W}{m}*1.8)+7$

where ;

$V_O_2 ( intensity ) = \dfrac{1 \ kcal min^{-1}*10^{-3}}{5}$

$V_O_2 ( intensity ) = \dfrac{6*1 \ kcal min^{-1}*10^{-3}}{5}$

$V_O_2 ( intensity ) = 0.0012$

∴ $0.0012 = (\dfrac{W}{75}*1.8)+7 \\ \\ W = \dfrac{0.0012-7}{1.8}*75 \\ \\ W = \dfrac{7*75}{1.8} \\ \\ W = 291.66 \ kg m /min$

Converting to watts;

Since; 6.118kg-m/min is = 1 watt

Then 291.66 kgm /min will be equal to 47.67 watts

≅ 47 watts

3 0

4 years ago

The count rate of a radioactive source decreases from 1600 counts per minute to 400 counts per minute in 12 hours. What is the h

kirill115 [55]

Answer:

$t_{1/2}=6 h$

Explanation:

Let's use the decay equation.

$A=A_{0}e^{-\lambda t}$

Where:

A is the activity at t time
A₀ is the initial activity
λ is the decay constant

We know that $\lambda=\frac{ln(2)}{t_{1/2}}$

So we have:

$\lambda=\frac{ln(A/A_{0})}{t}$

$\frac{ln(2)}{t_{1/2}}=\frac{ln(A/A_{0})}{t}$

$t_{1/2}=\frac{t*ln(2)}{ln(A/A_{0})}$

$t_{1/2}=6 h$

Therefore, the half-life of the source is 6 hours.

I hope it helps you!

4 0

3 years ago

In an economy, the demand for labor is given by the equation W = 15 - (1/200) L and the supply of labor is given by the equation

mr_godi [17]

Answer:

the equilibrium wage rate is 10 and the equilibrium quantity of labor is 1000 workers

Explanation:

The equilibrium wage rate and the equilibrium quantity of labor are found as the point where the equation of demand intercepts the equation of supply, so the equilibrium quantity of labor is:

$W_{Demand} = W_{Supply}$

15 - (1/200) L = 5 + (1/200) L

15 - 5 = (1/200) L + (1/200) L

10 = (2/200) L

(10*200)/2 = L

1000 = L

Then, the equilibrium wage rate is calculated using either the equation of demand for labor or the equation of supply of labor. If we use the equation of demand for labor, we get:

W = 15 - (1/200) L

W = 15 - (1/200) 1000

W = 10

Finally, the equilibrium wage rate is 10 and the equilibrium quantity of labor is 1000 workers

7 0

3 years ago

Identify the type of chemical reaction that is described.

Mashcka [7]

If its out and has been rained on it will rust if its like metal or iron stuff like that it will rust
the answer is rust
but no so quickly

5 0

4 years ago