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4 years ago

1.

Chemistry

2 answers:

yuradex [85]4 years ago

8 0

Answer: The average atomic mass of bromine is 79.91 amu.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

For isotope 1:

Mass of isotope 1 = 78.92 amu

Percentage abundance of isotope 1 = 50.54 %

Fractional abundance of isotope 1 = 0.5054

For isotope 2:

Mass of isotope 2 = 80.92 amu

Percentage abundance of isotope 2 = 49.46 %

Fractional abundance of isotope 2 = 0.4946

Putting values in equation 1, we get:

$\text{Average atomic mass of Bromine}=[(78.92\times 0.5054)+(80.92\times 0.4946)]$

$\text{Average atomic mass of Bromine}=79.91amu$

Hence, the average atomic mass of element bromine is 79.91 amu.

Katen [24]4 years ago

6 0

Answer:Tationia Rolon

Explanation:

Use this it might help:

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How many grams of NH3 can be prepared from the synthesis of 77.3 grams of nitrogen and 14.2 grams of hydrogen gas?

lbvjy [14]

Answer:

80.41 g

Explanation:

Data Given:

Mass of Nitrogen (N₂) = 77.3 g

Mass of Hydrogen (H₂) = 14.2 g

many grams of NH₃ = ?

Solution:

First we look at the balanced synthesis reaction

N₂ + 3 H₂ ------—> 2 NH₃

1 mol 3 mol

As 1 mole of Nitrogen react with 3 mole of hydrogen

Convert moles to mass

molar mass of N₂ = 2(14) = 28 g/mol

molar mass of H₂ = 2(1) + 2 g/mol

Now

N₂ + 3 H₂ ------—> 2 NH₃

1 mol (28 g/mol) 3 mol(2g/mol)

28 g 6 g

28 grams of N₂ react with 6 g of H₂

if 28 grams of N₂ produces 6 g of H₂ so how many grams of N₂ will react with 14.2 g of H₂.

Apply Unity Formula

28 g of N₂ ≅ 6 g of H₂

X g of N₂ ≅ 14.2 g of H₂

Do cross multiply

X g of N₂ = 28 g x 14.2 g / 6 g

X g of N₂ = 66.3 g

As we have given with 77. 3 g of N₂ but from this calculation we come to know that 66.3 g will react with 14.2 g of hydrogen and the remaining 10 g N₂ will be in excess

So, Hydrogen is limiting reactant in this reaction and the amount of NH₃ depends on the amount of hydrogen.

Now

To find mass of NH₃ we will do following calculation

Look at the reaction

As we Know

N₂ + 3 H₂ ------—> 2 NH₃

6 g 2 mol

So, 6 g of hydrogen gives 2 moles of NH₃, then how many moles of NH₃ will be produce by 14.2 g

Apply Unity Formula

6 g of H₂ ≅ 2 mol of NH₃

14.2 g of H₂ ≅ X mol of NH₃

Do cross multiply

X mol of NH₃= 14.2 g x 2 mol / 6 g

X mol of NH₃ = 4.73 mol

So, 14.2 g of hydrogen gives 4.73 moles of NH₃

Now

Convert moles of NH₃ to mass

Formula will be used

mass in grams = no. of moles x molar mass . . . . . . (2)

Molar mass of NH₃

Molar mass of NH₃ = 14 + 3(1)

Molar mass of NH₃ = 14 + 3 = 17 g/mol

Put values in equation 2

mass in grams = 4.73 mole x 17 g/mol

mass in grams = 80.41 g

mass of NH₃= 80.41 g

3 0

3 years ago

(hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles in liquid wat

SVETLANKA909090 [29]

The equilibrium constant expression for this reaction is $K_{eq} = \frac{[HOCl]^{2}}{[Cl_{2}]^{2}}$ . This is an example of a heterogeneous equilibrium wherein the states of the reactants and products are different. In such a case, only the concentration of the gaseous and aqueous substances are included in the equilibrium constant expression.

Further Explanation:

The equilibrium constant expression is the ratio of the concentration of the products and the concentration of reactants.

The guidelines in writing the equilibrium constant expressions are as follows:

Write molar concentration of each product in the numerator of the Keq expression.
Write the coefficient of the substance as the exponent of the molar concentration of the substance in the Keq expression.
Write the molar concentration of each reactant raised to its coefficient in the denominator.

Note: Pure substances (i.e. solids and liquids) are not included in the equilibrium constant expression as their concentrations are constant.

The numerical equivalent of the Keq expression is called the equilibrium constant. It has a specific value for a given temperature. The equilibrium constant provides information about the spontaneity and progress of an equilibrium reaction.

Learn More

Learn more about equilibrium constants brainly.com/question/4137132
Learn more about Le Chatelier's Principle brainly.com/question/12983923
Learn more about Gibbs Free Energy brainly.com/question/12979420

Keywords: equilibrium constant expression, equilibrium

6 0

3 years ago

What contains huge, floating rafts of algae. A. inter tidal area B.coral reef C.estuary

sertanlavr [38]

Best guess would be F or G.

3 0

3 years ago

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I need to know the measurements of this to the appropriate amount of significant figures

igor_vitrenko [27]

Answer:

it can be 63 or 63.5

Explanation:

7 0

3 years ago

You are planting flowers in large pots. You plan to plant flowers in 10 pots. 15 cups of potting soil will fill one pot. A bag o

dimaraw [331]

Answer:

I will need six (6) bags of potting soil

Explanation:

Since you plan on planting in 10 pots and need 15 cups of potting soil per pot, the total amount of potting soil you need (in cups) is 10 X 15 = 150 cups of potting soil.

We have that a bag contains 25 sups. to get the number of bags needed, we have to divide 150 by 25. This will give us 150 / 25 = 6 bags.

Therefore, I will need six (6) bags of potting soil

3 0

4 years ago