Answer:
(a) Moon has smaller diameter and lower density than earth
Explanation:
Moon has smaller diameter than earth earth has a diameter of 12742 km whereas moon has a diameter of 3474.21 km
So for density density is given by 
From the relation we can see that density is dependent on mass and volume directly proportional to mass and inversely proportional to diameter
But in case of earth and moon mass is more dominating than volume so density is less for moon than earth
<span>hair follicle
should be your answer</span>
Explanation:
The geometry of the BF 3 molecule is called trigonal planar (see Figure 5). The fluorine atoms are positioned at the vertices of an equilateral triangle. The F-B-F angle is 120° and all four atoms lie in the same plane.
The average speed is 10 m/s.
Explanation:
The motion of the object is divided into two parts.
In the first part, the object covers a distance of

In a time interval of

In the second part, the object is a t rest, so it covers a distance of

In a time interval of

The average speed for the trip is given by the ratio between the total distance and the total time taken, therefore:

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Answer:
Star A would be brighter than Star B
Explanation:
The apparent brightness of a star as perceived on Earth is dependent on its temperature, size, luminosity and distance from the Earth. Apparent brightness is the visible brightness to the eye at the surface of the Earth, while luminosity is the true brightness at the surface of the star.
A hotter star will radiate more energy per second per meter square of surface area. A larger star will have a greater surface area for radiation of energy, thus increasing the luminosity. For two identical stars, the difference in apparent brightness will be dependent on their distances from Earth.
Brightness and distance from earth have an inverse square relationship.
∝
Assuming the star is a point source of radiation, as distance from the source is increased, the radiation is distributed over a surface proportional to the distance form the source. As distance is further increased, the radiation is distributed over a larger surface area reducing the effective luminosity.
If one star (Star B) is twice as far from the earth as the first (Star A), the brightness of Star B will be
of Star A.
Thus, Star B will appear to be a quarter of the brightness of Star A. Or, Star A will appear to be 4 times as bright as Star B.