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Ainat [17]
3 years ago
13

Help me rearrange this formula. I've been trying but I can't remember how to do it.​

Physics
1 answer:
NikAS [45]3 years ago
7 0

-- Multiply each side of the formula by 2

-- Then divide each side by t

-- Then subtract V(i) from each side.

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4 years ago
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How is friction harmful??
gregori [183]
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4 0
3 years ago
An 18 gauge copper wire (the size usually used for lamp cords), with a diameter of 1.02 mm,1.02 mm, carries a constant current o
larisa86 [58]

Answer:

J = 2.044x10⁶ A/m²

v = 1.50x10⁻⁴ m/s

Explanation:  

The current density (J) of the copper wire is giving by:  

J = \frac {I}{A}

<em>where I: electric current and A: cross-sectional area of the copper wire</em>

<u>The cross-sectional area of the copper wire can be calculated by:</u>

A = \frac {\pi d^{2}}{4} = \frac {\pi (1.02 \cdot 10^{-3} m)^{2}}{4} = 8.17 \cdot 10^{-07} m^{2}         

<u>Substituting the calculated area in the equation (1) we have:</u>

J = \frac {1.67 A}{8.17 \cdot 10^{-7} m^{2}} = 2.044 \cdot 10^{6} \frac {A}{m^{2}}    

Hence, the current density is 2.044x10⁶ A/m².    

To find the drift speed (v), we need to use the next equation:

v = \frac {J}{n q}  

<em>where n: the free-electron density, q: module of the charge of the electron </em>

v = \frac {2.044 \cdot 10^{6} \frac {A}{m^{2}}}{(8.5 \cdot 10^{28} {m^{-3}}) (1.6 \cdot 10^{-19} C)}  

v = 1.50 \cdot 10^{-04} \frac {m}{s}                            

So, the drift speed is 1.50x10⁻⁴ m/s.

Have a nice day!    

4 0
4 years ago
Read 2 more answers
What help in reversing direction of current of current​
Novay_Z [31]

Answer:

<em>To reverse the direction of an electric current, we simply reverse the voltage either automatically with the help of some switching circuitry or manually by changing the voltage source terminals connection.  </em>

Explanation:

For electric current to flow, there must be a potential difference, usually referred to as the voltage. The electric current flow is analogous to the flow of water under the action of a pump, through a series of pipe connections. The voltage is similar to the driving action of the pump, and current flows the same way water flows. The resistance due to drag on the pipe wall is equivalent to electric resistance. For current to flow in the reverse direction, the voltage or rather, the potential difference is changed, causing the current to flow in the opposite direction. This can be done by switching the terminals of the voltage source, or by automatic means. The automatic switching can be done with a transistor based circuitry.

3 0
4 years ago
A person wishes to heat pot of fresh water from 20°C to 100°C in order to boil water for pasta. They calculate that their pot ho
nasty-shy [4]
Given:
Water, 2 kilograms
T1 = 20 degrees Celsius, T2 = 100 degrees Celsius.  

Required:
Heat produced  

Solution:
Q (heat) = nRT = nR(T2 = T1)
Q (heat) = 2 kilograms (4.184 kiloJoules per kilogram Celsius) (100 degrees Celsius – 20 degrees Celsius)
<u>Q (heat) = 669.42 Joules
</u>This is the amount of heat produced in boiling 2 kg of water.
6 0
4 years ago
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