Question

What is the volume of 3.2 moles of chlorine gas (Cl2) at 295 K and 1.1 atm?​

Answer 1

Answer:

$\boxed{\text{70 L}}$

Explanation:

We can use the Ideal Gas Law to solve this problem

pV = nRT

Data:

p = 1.1 atm

n = 3.2 mol

R = 0.082 16 L·atm·K⁻¹mol⁻¹

T = 295 K

Calculation:

$\begin{array}{rcl}1.1V\text{ atm} & = & \text{3.2 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{295 K}\\1.1V & = & \text{77.5 L}\\\\V & = &\dfrac {\text{77.5 L}}{1.1}\\\\V & = & \text{70 L}\\\end{array}\\\text{The volume is }\boxed{\textbf{70 L}}$