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Korvikt [17]
4 years ago
5

Question 9

Chemistry
1 answer:
Nadusha1986 [10]4 years ago
8 0

Answer:

Mass of carbon tetrachloride 135.15 g.

Explanation:

Given data:

Volume of carbon tetrachloride = 85.0 mL or 85.0 cm³

Density of carbon tetrachloride = 1.59 g/cm³

Mass of carbon tetrachloride = ?

Solution:

Formula:

D=m/v

D= density

m=mass

V=volume

Now we will put the values in formula:

1.59 g/cm³ = m / 85.0 cm³

m = 1.59 g/cm³ ×85.0 cm³

m = 135.15 g

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MA_775_DIABLO [31]

Answer:

b

Explanation:

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4 0
3 years ago
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3. If 90.0 grams of barium chloride react with sulfuric acid, how many
PtichkaEL [24]

Answer:

The answer to your question is 100.8 g

Explanation:

Data

  mass of Barium chloride = 90 g

  mass of Barium sulfate = ?

Balanced chemical reaction

    BaCl₂  +  H₂SO₄   ⇒    BaSO₄  +  2HCl

Process

1.- Calculate the molar mass of BaCl₂ and BaSO₄

BaCl₂ = 137.3 + (2 x 35.5) = 208.3g

BaSO₄ = 137.3 + 32 + (16 x 4) = 233.3g

2.- Use proportions to find the mass of BaSO₄

              208.3 g of BaCl₂ --------------------- 233.3 g of BaSO₄

                90 g of BaCl₂    ---------------------   x

                              x = (90 x 233.3) / 208.3

                              x = 20997/ 208.3

                              x = 100.8 g

3.- Conclusion

There will be produced 100.8 g of BaSO₄          

4 0
3 years ago
(+1)+(-1)=||<br> (2)+(-2) = 0<br> 20+1) + (-2) = _<br> (+3) + 3(-1)=<br> 37+2) + 2-3] =
larisa86 [58]
  • 1+(-1)=0
  • 2+(-2)=0
  • 20+1+(-2)=19
  • 3+3(-1)=0
  • 37+2+2-3=38
6 0
4 years ago
Rank the four gases (air, exhaled air, gas produced from the decomposition of H2O2, gas from decomposition of NaHCO3) in order o
TEA [102]
Decomposition of sodium bicarbonate produces pure carbon dioxide and decomposition of hydrogen peroxide produces pure oxygen.
The amount of carbon dioxide in exhaled air is greater than that in regular air. Thus, the order is:

gas from decomposition of NaHCO₃ → Exhaled air → Air → gas from the decomposition of H₂O₂
6 0
4 years ago
Rhodium, a metal used as a catalyst and in jewelry, currently sells for $1500. per troy ounce. If 6.022 x 10^23 rhodium atoms ha
USPshnik [31]

Answer:

2.19 \times 10^{-4} \mathrm{Rh}

Explanation:

Atomic mass of Nickel = 58.69 g/mol

Mass of 1 mole of nickel atom = 58.69 gm

Now, mass of 1 nickel atom = Gram atomic mass/Avogadro number

=\frac{58.69}{6.023\times10^{22}} =9.744\times10^{23} g/atom

Now, price of Rhodium =$1500 per troy ounce

Price of nickel in market  = 0.577$/oz

No. of rhodium atoms needed to buy 1 nickel atom is

9.744 \times 10^{-23} \mathrm{g} \times \frac{1 \mathrm{oz}}{31.1035 \mathrm{g}} \times \frac{0.577 \mathrm{s}}{1 \mathrm{oz}} \times \frac{1 \mathrm{oz}}{1500 \mathrm{s}}

\quad \times \frac{31.1035 \mathrm{g}}{1 \mathrm{oz}} \times \frac{6.023 \times 10^{23} \mathrm{Rh} \text { atoms }}{102.9 \mathrm{g}}=2.19 \times 10^{-4} \mathrm{Rh} \text { atoms }

4 0
4 years ago
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