3 years ago

If the index of refraction of a lens is 1.5, how fast does light travel in the lens?

Physics

2 answers:

lina2011 [118]3 years ago

7 0

Answer:

Explanation:

Len [333]3 years ago

5 0

The speed of light in a material is given by:
$v= \frac{c}{n}$
where
$c=3 \cdot 10^8 m/s$ is the speed of light in vacuum
n is the refractive index of the material

The lens in this problem has a refractive index of n=1.50, therefore the speed of light in the lens is
$v= \frac{c}{n}= \frac{3 \cdot 10^8 m/s}{1.50}=2 \cdot 10^8 m/s$

And the correct answer is C).

You might be interested in

A train on a straight track goes in the positive direction for 5.9 km, and then backs up for 3.8 km

kenny6666 [7]

Answer:

2.1km

Explanation:

Ill take it as u are talking about the displacement

Since displacement has negatives and positves

5.9 - 3.8 = 2.1km

6 0

3 years ago

An observer on the earth sees a spaceship approaching at 0.54c. The ship then launches an exploration vehicle that, according to

AURORKA [14]

Answer:

Explanation:

Expression for relative velocity

= $\frac{v_1+v_2}{1+\frac{v_1v_2}{c^2} }$

= (.54 + .82 )c/ $1+ \frac{.54 \times.82}{1}$

= 1.36 c / 1.4428

= .94 c

β = .94

6 0

3 years ago

A crate is pushed horizontally by a horizontal force 527.018 N . Sliding friction resists the motion, and the kinetic coefficien

gulaghasi [49]

Answer:

m= 10 kg a = 52 m / s²

Explanation:

For this problem we must use Newton's second law, let's apply it to each axis

X axis

F - fr = ma

The equation for the force of friction is

-fr = miu N

Axis y

N- W = 0

N = mg

Let's replace and calculate laceration

F - miu (mg) = ma

a = F / m - mi g

a = 527.018 / m - 0.17 9.8

We must know the mass of the body suppose m = 10 kg

a = 527.018 / 10 - 1,666

a = 52 m / s²

5 0

3 years ago

Tortoise and the Hare

Tanya [424]

The answer would be D. <span>The tortoise moved at a constant velocity throughout the race; the hare stopped to rest periodically.

Hope this helped. Good luck!</span>

3 0

3 years ago

Read 2 more answers

The position of a 55 g oscillating mass is given by x(t)=(2.0cm)cos(10t), where t is in seconds. determine the velocity at t=0.4

NNADVOKAT [17]

The position of the mass is given by (in cm):
$x(t)=2 \cos (10 t)$
The velocity is the derivative of the position:
$v(t) = \frac{dx(t)}{dt} =-10\cdot 2 \sin (10t)=-20 \sin (10t)$
Substituting t=0.40 s, we can find the velocity at this time:
$v(0.40 s)= -20 \sin (10 \cdot 0.4)=15 cm/s=15 \cdot 10^{-2}m/s$

5 0

3 years ago

Read 2 more answers