Answer:
F = - k (x-xo) a graph of the weight or applied force against the elongation obtaining a line already proves Hooke's law.
Explanation:
The student wants to prove hooke's law which has the form
F = - k (x-xo)
To do this we hang the spring in a vertical position and mark the equilibrium position on a tape measure, to simplify the calculations we can make this point zero by placing our reference system in this position.
Now for a series of known masses let's get them one by one and measure the spring elongation, building a table of weight vs elongation,
we must be careful when hanging the weights so as not to create oscillations in the spring
we look for the mass of each weight
W = mg
m = W / g
and we write them in a new column, we make a graph of the weight or applied force against the elongation and it should give a straight line; the slope of this line is sought, which is the spring constant.
The fact of obtaining a line already proves Hooke's law.
Answer:
b) 4781 N
Explanation:
Because there is a redius do this question is talking about the acceleration force which= mv^2/r
so a=15^2/80=2.8125 m^2/s
so the force will be = m.a
F =1700×2.8125=4781.25 N
Hello there
the answer is
Let the initial position from where the ball is kickedat angle 45 deg, be A. The Horizontal range of the ball (AC) is V2 Sin2θ / g = 38.76 Meters
thank you
Answer:
The electric force on the top charge is 
.
Explanation:
Given that,
Electric charges in a thundercloud, 
The distance between charges, d = 2.3 km = 2300 m
Let F is the electric force on the top charge. The electric force is given by the formula as :
or
So, the electric force on the top charge is . Hence, this is the required solution.
Answer:
<h2>False or No </h2>
Explanation:
Gamma rays has strongly focused energy, a gamma burst rays cannot be seen or detected.
It can only be detected on far galaxies.
