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3 years ago

The sunlight that reaches Earth is generated by a transformation of _____.

Physics

1 answer:

Georgia [21]3 years ago

6 0

nuclear energy

Explanation:

The sunlight that reaches earth is generated by a transformation of nuclear energy. Radiant energy is a from of energy that reaches the earth from nuclear reactions in the core of the sun.

In this process, light nuclei combines to form larger ones through the process of nuclear fusion.
This process does not conserve energy and mass is converted to energy.
The nuclear reaction produces huge energy that goes into the solar system space and lights it up.
Therefore, it is a transformation of nuclear energy into radiant energy.
The radiant energy is made up of electromagnetic radiations.

Learn more;

Nuclear reactions brainly.com/question/10094982

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3 years ago

Draw a winding path that covers a distance of 70 miles and finishes with a displacement 20 miles soulthwest of the starting poin

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2 years ago

A 19 nC charge is moved in a uniform electric field. The electric field does 5.3 μJ of work as the charge moves from point A to

Marizza181 [45]

Answer:

The potential difference between points A and B is 278.95 volts.

The potential difference between points B and C is -642.10 volts.

The potential difference between points A and C is -363.15 volts.

Explanation:

Given :

Charge of the particle, q = 19 nC = 19 x 10⁻⁹ C

Work is done to move a charge from point A to B, W₁ = 5.3 μJ

Work done to move a charge from point B to C, W₂ = -12.2 μJ

Let V₁ be the potential difference between point A and B, V₂ be the potential difference between point B and C and V₃ be the potential difference between point A and C.

The relation between work done and potential difference is:

W = qV

V = W/q ....(1)

Using equation (1), the potential difference between points A and B is:

$V_{1}=\frac{W_{1} }{q}$

Substitute the suitable values in the above equation.

$V_{1} =\frac{5.3\times10^{-6} }{19\times10^{-9} }$

V₁ = 278.95 V

Using equation (1), the potential difference between points B and C is:

$V_{2}=\frac{W_{2} }{q}$

Substitute the suitable values in the above equation.

$V_{2} =\frac{-12.2\times10^{-6} }{19\times10^{-9} }$

V₂ = -642.10 V

The potential difference between points A and C is:

V₃ = V₁ + V₂

V₃ = 278.95 - 642.10

V₃ = -363.15 V

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