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stira [4]
3 years ago
14

The sunlight that reaches Earth is generated by a transformation of _____.

Physics
1 answer:
Georgia [21]3 years ago
6 0

nuclear energy

Explanation:

The sunlight that reaches earth is generated by a transformation of nuclear energy. Radiant energy is a from of energy that reaches the earth from nuclear reactions in the core of the sun.

  • In this process, light nuclei combines to form larger ones through the process of nuclear fusion.
  • This process does not conserve energy and mass is converted to energy.
  • The nuclear reaction produces huge energy that goes into the solar system space and lights it up.
  • Therefore, it is a transformation of nuclear energy into radiant energy.
  • The radiant energy is made up of electromagnetic radiations.

Learn more;

Nuclear reactions brainly.com/question/10094982

#learnwithBrainly

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A uniform magnetic field passes through a horizontal circular wire loop at an angle 19.5 ∘ from the vertical. The magnitude of t
nlexa [21]

To solve this problem, we will apply the concepts related to Faraday's law that describes the behavior of the emf induced in the loop. Remember that this can be expressed as the product between the number of loops and the variation of the magnetic flux per unit of time. At the same time the magnetic flux through a loop of cross sectional area is,

\Phi = BA Cos \theta

Here,

\theta = Angle between areal vector and magnetic field direction.

According to Faraday's law, induced emf in the loop is,

\epsilon= -N \frac{d\Phi }{dt}

\epsilon = -N \frac{(BAcos\theta)}{dt}

\epsilon = -NAcos\theta \frac{dB}{dt}

\epsilon = -N\pi r^2 cos\theta \frac{d}{dt} ( ( 3.75 T ) + ( 3.05T/s ) t + ( -6.95 T/s^2 ) t^2)

\epsilon = -N\pi r^2 cos\theta( (3.05T/s)-(13.9T/s)t )

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\epsilon = -(1) \pi (0.220m)^2 cos(19.5\°)(  (3.05T/s)-(13.9T/s)(5.71s))

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Therefore the magnitude of the induced emf is 10.9V

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3 years ago
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