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Brut [27]
3 years ago
15

2. The amount of charge and the distance from the charge determine the...

Physics
2 answers:
olasank [31]3 years ago
8 0

Answer:

Strength of the electric field

Explanation:

The amount of charge and the distance from the charge determine the strength of the electric field.

Mathematically, it can be written as :

E=\dfrac{1}{4\pi \epsilon_0}\dfrac{q}{r^2}

where,

q is the electric charge

r is the distance between the charges

It can be also defined as the electric force per unit electric charge. Hence, the correct option is (c) " Strength of the electric field ".

cricket20 [7]3 years ago
7 0

Answer:

the answer is c Strength of the electric field

Explanation:

it is that bcause

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An astronaut is doing repairs on the international Space Station. She throws a hammer into space with a velocity of 3m/s. How mu
Rainbow [258]

Answer:

The force is 15N

Explanation:

The formula is Force= mass × velocity.

From the question mass is 5kg, velocity is 3m/s.

F= 5×3

F= 15Newton.

Therefore the force is 15N.

3 0
3 years ago
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Identify the role of organisms in this food chain.
Llana [10]

Answer:

the grass is the producer, the mushroom is the decomposer, the dragonfly is the primary consumer, the frog is the secondary, and the hawk is the tertiary consumer.

Explanation:

Hope this helps :)

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3 years ago
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Select all the correct locations on the image. Select the volume units that are greater than one liter.
dalvyx [7]

Answer:

N/A

Explanation:

No Image provided

5 0
4 years ago
Measurements made on an operating centrifugal pump indicate that for a flow rate of 240 gpm, 6 HP are being consumed. The operat
Ludmilka [50]

Answer:

62.1 ft

Explanation:

We know that 1 gpm= 0.0022 ft^{3}/s hence 240 gpm will be

240*0.0022=0.528 ft^{3}/s

From the formula of obtaining efficiency

\eta=\frac {\gamma Q h_a}{500W_{in}} and making h_a the subject we have

h_a=\frac {\eta*550*W_{in}}{\gamma Q} where Q is flow rate, \gamma is specific weight of water, h_a is actual head rise and W_{in} is the power input to the compressor

Substituting 0.62 for \eta, 6hp for W_{in}, 62.4 lb/ft^{3} for \gamma and 0.528 ft^{3}/s for Q then

h_a=\frac {0.62*550*6}{62.4*0.528}=\frac {2046}{32.9472}=62.09936\approx 62.1 ft

Therefore, actual head rise of the water being pumped is 62.1 ft

6 0
3 years ago
An object falls freely from rest near the surface of Earth. What is the speed of the object after having fallen a distance at 4.
bija089 [108]
V^2 = vi^2  + 2as

vi = 0 in this case
a = 9.8 m/s^2

So,

V^2 =  2 * 9.8 * 490
v = 98.05 m/s

hope this helps

3 0
3 years ago
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