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3 years ago

Is 1/3 a terminating decimal

1 answer:

3 0

A terminating decimal is a decimal that STOPS, meaning it doesn't go on forever.

So, we will divide and see.

1 ÷ 3 = <span>0.3333333............

So NO this is NOT a terminating decimal, but a repeating decimal.

Hope i helped ya!!!!!! </span>

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NARA [144]

I believe it is x-4 but might be totally wrong

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3 years ago

Compute 5/3 divided by (-1/2 times -4)

romanna [79]

Answer:

13.3

Step-by-step explanation:

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3 years ago

Read 2 more answers

A certain country has $10 billion in paper currency in circulation, and each day $50 million comes into the country's banks. The

mash [69]

Answer:

$\bf x(t)=10(1-e^{-0.005*t})$

Step-by-step explanation:

The differential equation

$\bf \displaystyle\frac{dx}{dt}=0.005(10-x)$

can be solved by separation of variables. Write the equation as

$\bf \displaystyle\frac{dx}{10-x}=0.005dt$

Integrate on both sides

$\bf \int\displaystyle\frac{dx}{10-x}=\int0.005dt\Rightarrow -ln(10-x)=0.005t+C\Rightarrow\\\\\Rightarrow ln(10-x)^{-1}=0.005t+C\Rightarrow (10-x)^{-1}=e^{0.005t}e^C$

where C is a constant.

$\bf e^C$ is also a constant and we will keep calling it C, (there is no reason to change the letter). We have then

$\bf (10-x)^{-1}=Ce^{0.005t}\Rightarrow \displaystyle\frac{1}{10-x}=Ce^{0.005t}\Rightarrow 10-x=\displaystyle\frac{1}{Ce^{0.005t}}\Rightarrow\\\\\Rightarrow x(t)=10-(1/C)e{-0.005t}$

(1/C) is a constant, and for the same reason we will keep calling it C. So the general solution is

$\bf x(t)=10-Ce^{-0.005t}$

Now, we use the initial condition x(0)=0

$\bf x(0)=10-Ce^{-0.005*0}=0\Rightarrow C=10$

and the particular solution is

$\bf x(t)=10-10e^{-0.005*t}=10(1-e^{-0.005*t})\\\\\boxed{x(t)=10(1-e^{-0.005*t})}$

7 0

3 years ago

What is the perimeter of a rectangle that has a length of 15 centimeters?

Georgia [21]

The perimeter is 60 cm

5 0

3 years ago

Please help! Find the value of X. Round to the nearest tenth. acellus

just olya [345]

9514 1404 393

Answer:

38.2°

Step-by-step explanation:

The law of sines tells you ...

sin(x)/15 = sin(27°)/11

sin(x) = (15/11)sin(27°) . . . . . multiply by 15

x = arcsin((15/11)sin(27°)) ≈ arcsin(0.619078) ≈ 38.2488°

x ≈ 38.2°

_____

<em>Additional comment</em>

In "law of sines" problems, you need to identify a side and opposite angle that you know both values of. Then, you need to identify whether you're looking for an angle or a side, and whether its opposite side or angle is known. If two angles are known, you can always figure the third from the sum of angles in a triangle.

Here, we have angle 27° opposite side 11. We are looking for an angle, and we know its opposite side. This lets us use the ratio formula directly. Since the angle is the unknown, it is useful to write the equation with sines on top and sides on the bottom.

The given angle is opposite the shorter of the given sides, so this triangle has two solutions. We assume that we want the solution that is an acute angle (141.8° is the other solution). That assumption is based on the drawing. Usually, you're cautioned not to take the drawings at face value.

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3 years ago