<u>Answer:</u> The equilibrium concentration of 
is 0.332 M
<u>Explanation:</u>
We are given:
Initial concentration of = 2.00 M
The given chemical equation follows:
<u>Initial:</u> 2.00
<u>At eqllm:</u> 2.00-2x x x
The expression of 
for above equation follows:
![K_c=\frac{[CO_2][CF_4]}{[COF_2]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCO_2%5D%5BCF_4%5D%7D%7B%5BCOF_2%5D%5E2%7D)
We are given:
Putting values in above expression, we get:
Neglecting the value of x = 1.25 because equilibrium concentration of the reactant will becomes negative, which is not possible
So, equilibrium concentration of ![COF_2=(2.00-2x)=[2.00-(2\times 0.834)]=0.332M](https://tex.z-dn.net/?f=COF_2%3D%282.00-2x%29%3D%5B2.00-%282%5Ctimes%200.834%29%5D%3D0.332M)
Hence, the equilibrium concentration of is 0.332 M
Its the answer b, because oil has a great density, therefore, when you mix them together the oil will be below and the above of it.
100 by 500 ml so if you put 50 ml in 630torr it would evaporate
Explanation:
it is more than ¹00 celcwius so it would eveporate
Answer: thats alot of reading
Explanation:
Answer:
The answer to your question is: a = 2.1 m/s²
Explanation:
Data
Acceleration : ?
Mass = 2000 kg
Force = 4200 N
Formula
Newton's second law of motion F = ma
a = F / m
Substitution
a = 4200 N / 2000 kg
a = 2.1 m/s²
