Answer:
Yes the reaction occur when aqueous solutions happened
Answer:
V = 1.84 × 10³ L
Explanation:
You need to use the Ideal Gas Law and solve for volume.
PV = nRT
V = nRT/P
First, you need to convert the pressure to atm.
1 atm = 760 mm Hg
948/760 = 1.247 atm
Next, convert grams of xenon to moles. The molar mass is 131.293 g/mol.
128/131.293 = 0.975 mol
You now have all of the values needed.
P = 1.247 atm
n = 0.975 mol
R = 8.314 J/mol*K
T = 283 K
Plug the values in and solve.
V = nRT/P
V = (0.975 × 8.314 × 283)/1.247
V = 1.84 × 10³ L
The volume of the sample will be 1.84 × 10³ L.
Answer:
(a)²⁴²₉₄Pu ⇒ ⁴₂He + ²³⁸₉₂U ⇒ ²³⁸₉₂U + ⁰₀γ
(b) 4.898 MeV
Explanation:
In the nuclear reaction, it was stated that plutonium-242 decayed firstly to uranium-238 and alpha, and lastly to a stable uranium-238 by emitting a gamma ray. The balanced equation for the nuclear reactions is shown below:
(a)²⁴²₉₄Pu ⇒ ⁴₂He + ²³⁸₉₂U ⇒ ²³⁸₉₂U + ⁰₀γ
(b) The energy emitted by releasing a gamma ray is calculated using:
E = hc/λ
where
h = 4.136*10^-15 eV.s
c = 299792458 m/s
λ = 0.02757 nm = 0.02757*10^-9 m
Therefore:
E = (4.136*10^-15)*(299792458)/0.02757*10^-9 = 44974.31 eV
The total energy if the stable 238U was produced directly would be
4.853*10^6 + 44974.31 = 4.898 MeV
