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4 years ago

Select the correct answer from each drop-down menu.

Chemistry

2 answers:

seraphim [82]4 years ago

5 0

1. protons and neutrons

2. electrons

liraira [26]4 years ago

4 0

Answer:

Protons and neutrons, Electrons

Explanation:

Protons and electrons are found in the center of the nucleus. The atomic mass is the summation of the number of neutrons and protons. Electrons orbit around the nucleus in an atom. The atomic number is equal to the number of electrons which is also equal to the number of protons.

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A thermometer reads a pressure of 120 kPa at 0 ˚C. What is the temperature when the thermometer reads a pressure of 80 kPa? (Cel

Mariulka [41]

Answer:

T₂ = 182 K

Explanation:

Given that,

Initial pressure, P₁ = 120 kPa

Initial temperature, T₁ = 0˚C = 273 K

We need to find the final temperature when the pressure is 80 kPa.

We know that, Gay Lussac's Formula is :

$\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\\\\T_2=\dfrac{P_2T_1}{P_1}\\\\T_2=\dfrac{80\ kPa\times 273}{120\ kPa}\\\\T_2=182\ K$

So, the new temperature is equal to 182 K.

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3 years ago

Oh, no! You just spilled 85.00 mL of 1.500 M sulfuric acid on your lab bench and need to clean it up immediately! Right next to

vredina [299]

Explanation:

We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.

$H_2SO_4(aq) + 2NaHCO_3(s) \rightarrow Na2SO_4(aq) + 2H_2O(l) + 2CO_2(g)$

Next we will calculate how many moles of $H_2SO_4$ are present in 85.00 mL of 1.500 M sulfuric acid.

As, Molarity = $\frac{\text{moles of solute}}{\text{liters of solution
}}$

1.500 M = $\frac{n}{0.08500 L
}$

n = 0.1275 mol $H_2SO_4$

Now set up and solve a stoichiometric conversion from moles of $H_2SO_4$ to grams of $NaHCO_3$ . As, the molar mass of $NaHCO_3$ is 84.01 g/mol.

$0.1275 mol H_2SO_4 \times (\frac{2 mol NaHCO_3}{1 mol H_2SO_4}) \times (\frac{84.01 g NaHCO_3}{1 mol NaHCO_3})$

= 21.42 g $NaHCO_3$

So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.

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3 years ago

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Elenna [48]

I’m not sure what this says could you translate it to English please?

6 0

4 years ago

Salicylic acid (C7H6O3) reacts with acetic anhydride (C4H6O3) to form acetylsalicylic acid (C9H8O4). 2C7H6O3(aq) + C4H6O3(aq) 2C

Yuki888 [10]

Answer:

The limiting reactant is salicylic acid.

Explanation:

From the equation of reaction,

1 mole of acetic anhydride (C4H6O3) (102g) reacts with 2 moles of salicylic acid (C7H6O3) (276 g)

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216.5 grams of salicylic acid that is required to react with 80 grams of acetic anhydride.

The available mass of salicylic acid is 70 grams which makes salicylic acid the limiting reactant.

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3 years ago

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