Answer:
In asexual reproduction an exact genetic copy of the parent organism is produced. Unlike sexual reproduction, asexual reproduction only introduces genetic variation into the population if a random mutation in the organism's DNA is passed on to the offspring.
Explanation:
Answer:
pH: If it's to much on either the alkaine or the acid side the enzymes will vary
Explanation:
The chance of the offsprings with stripe on head is 50%.
Option A.
<h3><u>Explanation:</u></h3>
Here according to the figures, the male is the brown one which has no stripe on his head as mentioned, and the female is the pink one who has a stripe on her head. The gene for the head stripe is denoted by H.
So the genotype of the father which is given as Hh. He is heterozygous.
The genotype of the mother should be hh as she has stripe and she must be homozygous recessive to have it.
So the gametes from father is H and h. Whereas the gametes from mother is only h.
So the genotype of the offsprings are Hh and hh as 50% each.
So the probability of the offspring being striped head is 50%.
Answer:
The correct answer is the formation of pyruvate from glucose willl be energetically less favorable.
Explanation:
According to the question matunt yeast has a shorter glycolytic pathay catalysing a follwing reaction
Glyceraldehyde-3-phosphate+H2O+NAD+ = 3-phosphoglycerate
So in the mutatant the formation of 1,3- bisphosphoglycerate is not occurring.The glyceraldehyde-3-phosphate is directly converted into 3-phosphoglycerate.
As a result the substrate level phosphorylation step that deals with formation of 3-phosphoglycerate from 1,3 bisphosphoglycerate is not occurring.
From this point of view it can be said that less energy will be formed in the mutant during glycolysis than that of normal one.
So the formation of pyruvate from glucose will be energetically less favorable.
