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valentinak56 [21]
3 years ago
10

How much energy is generated from freezing 2.5 g water

Chemistry
1 answer:
zvonat [6]3 years ago
6 0
200 calories.
Explanation:
The (latent) heat of fusion of a material, is either one of:
1) the heat required to melt the material without
temperature change or
2) the heat removed from the material to freeze it
without temperature change.
For water this latent heat is 80 cal/g. Multiply this by
2.5 g to get 200 cal.
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In some types of alcohol digestion, alcohol C_2 H_5 OHC 2 ​ H 5 ​ OHC, start subscript, 2, end subscript, H, start subscript, 5,
kari74 [83]

Answer:

This is the typical route of alcohol metabolism, where in the liver it is first transformed to acetaldehyde and then to acetate.

Explanation:

Ethanol is not digested but absorbed and follows its metabolic pathway in the liver, producing in the first instance acetaldehyde, which is the main substance that causes the hangover and then this compound is transformed into the final product, which is acetate Later acetate is metabolized to Acetyl-CoA. The enzyme responsible for the metabolism of ethanol is alcohol dehydrogenase in the liver, and for the cytochrome P-450 dependent system and for catalase in the liver.

3 0
3 years ago
list the four quantum numbers from LAST electron of each of the following elements in their ground state: sodium, nitrogen, oxyg
Rasek [7]

Explanation:

The four quantum  numbers gives the position of the orbital, its spatial orientation, the shape of the orbital and the spin of the an electron in the orbital.

The principal quantum number(n) gives the main energy level in which the orbital is located; n = 1,2,3,4....

Azimuthal or secondary quantum number (l) gives the shape of the orbitals an they take values l = 0,1,2,3.... and their names are s for 0, p for 1, d for 2 and f for 3.

Magnetic quantum number gives the spatial orientation or degeneracy of the orbitals in the subshell.

Spin quantum number gives the spinning of the electrons

Electronic configuration:

Na = 1s² 2s² 2p⁶ 3s¹

   The last electron enters the 3s¹

           n = 3

            l = 0

           m = 0

            spin =+ or - \frac{1}{2}

N = 1s² 2s²  2p³

           last electron enters 2p³

              n = 2

              l = 1

               m = -1, 0, 1

               spin = + or - \frac{1}{2}

O = 1s² 2s² 2p²

    last electron enters  2p²

             n = 2

              l = 1

               m = -1, 0, 1

               spin = + or - \frac{1}{2}

Cl =1s² 2s² 2p⁶ 3s² 3p⁵

     last electron enters 3p⁵

               n = 3

              l = 1

               m = -1, 0, 1

               spin = + or - \frac{1}{2}

S = 1s² 2s² 2p⁶ 3s² 3p⁴

      last electron enters 3p⁴

               n = 3

              l = 1

               m = -1, 0, 1

               spin = + or - \frac{1}{2}

learn more:

Quantum number brainly.com/question/9288609

#learnwithBrainly

5 0
4 years ago
Explain why the metals conduct electricity
Whitepunk [10]

Answer:

Metals conduct electricity because the electrons inside the metal are relatively free to move. So when electricity is pass through metals, electrons carry electricity and spread it all over the metal. The mobility of electrons is the reason why metals conduct electricity.

5 0
3 years ago
How many independent variables should you have in an experiment?
stepladder [879]

Answer:

One independent variable

Explanation:

The other variables are called controlled variables because the experiment is designed to keep them at an unchanging value, known as "controlling" a variable. A valid experiment should have only one independent variable.

8 0
3 years ago
Can someone solve this problem 5
Westkost [7]

Answer:

2

Step-by-step explanation:

A. Moles before mixing

<em>Beaker I: </em>

Moles of H⁺ = 0.100 L × 0.03 mol/1 L

                   = 3 × 10⁻³ mol

<em>Beaker II: </em>

Beaker II is basic, because [H⁺] < 10⁻⁷ mol·L⁻¹.

        H⁺][OH⁻] = 1 × 10⁻¹⁴   Divide each side by [H⁺]

             [OH⁻] = (1 × 10⁻¹⁴)/[H⁺]

             [OH⁻] = (1 × 10⁻¹⁴)/(1 × 10⁻¹²)

             [OH⁻] = 0.01 mol·L⁻¹

Moles of OH⁻ = 0.100 L × 0.01 mol/1 L

                      = 1 × 10⁻³ mol

B. Moles after mixing

                 H⁺    +    OH⁻   ⟶ H₂O

I/mol:      3 × 10⁻³   1 × 10⁻³

C/mol:   -1 × 10⁻³  -1 × 10⁻³

E/mol:    2 × 10⁻³          0

You have more moles of acid than base, so the base will be completely neutralized when you mix the solutions.

You will end up with 2 × 10⁻³ mol of H⁺ in 200 mL of solution.


C. pH

 [H⁺] = (2 × 10⁻³ mol)/(0.200 L)

        = 1 × 10⁻² mol·L⁻¹

 pH = -log[H⁺ ]

       = -log(1 × 10⁻²)

       = 2

6 0
3 years ago
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