Answer:
This is the typical route of alcohol metabolism, where in the liver it is first transformed to acetaldehyde and then to acetate.
Explanation:
Ethanol is not digested but absorbed and follows its metabolic pathway in the liver, producing in the first instance acetaldehyde, which is the main substance that causes the hangover and then this compound is transformed into the final product, which is acetate Later acetate is metabolized to Acetyl-CoA. The enzyme responsible for the metabolism of ethanol is alcohol dehydrogenase in the liver, and for the cytochrome P-450 dependent system and for catalase in the liver.
Explanation:
The four quantum numbers gives the position of the orbital, its spatial orientation, the shape of the orbital and the spin of the an electron in the orbital.
The principal quantum number(n) gives the main energy level in which the orbital is located; n = 1,2,3,4....
Azimuthal or secondary quantum number (l) gives the shape of the orbitals an they take values l = 0,1,2,3.... and their names are s for 0, p for 1, d for 2 and f for 3.
Magnetic quantum number gives the spatial orientation or degeneracy of the orbitals in the subshell.
Spin quantum number gives the spinning of the electrons
Electronic configuration:
Na = 1s² 2s² 2p⁶ 3s¹
The last electron enters the 3s¹
n = 3
l = 0
m = 0
spin =+ or - 
N = 1s² 2s² 2p³
last electron enters 2p³
n = 2
l = 1
m = -1, 0, 1
spin = + or - 
O = 1s² 2s² 2p²
last electron enters 2p²
n = 2
l = 1
m = -1, 0, 1
spin = + or - 
Cl =1s² 2s² 2p⁶ 3s² 3p⁵
last electron enters 3p⁵
n = 3
l = 1
m = -1, 0, 1
spin = + or - 
S = 1s² 2s² 2p⁶ 3s² 3p⁴
last electron enters 3p⁴
n = 3
l = 1
m = -1, 0, 1
spin = + or - 
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Answer:
Metals conduct electricity because the electrons inside the metal are relatively free to move. So when electricity is pass through metals, electrons carry electricity and spread it all over the metal. The mobility of electrons is the reason why metals conduct electricity.
Answer:
One independent variable
Explanation:
The other variables are called controlled variables because the experiment is designed to keep them at an unchanging value, known as "controlling" a variable. A valid experiment should have only one independent variable.
Answer:
2
Step-by-step explanation:
A. Moles before mixing
<em>Beaker I:
</em>
Moles of H⁺ = 0.100 L × 0.03 mol/1 L
= 3 × 10⁻³ mol
<em>Beaker II:
</em>
Beaker II is basic, because [H⁺] < 10⁻⁷ mol·L⁻¹.
H⁺][OH⁻] = 1 × 10⁻¹⁴ Divide each side by [H⁺]
[OH⁻] = (1 × 10⁻¹⁴)/[H⁺]
[OH⁻] = (1 × 10⁻¹⁴)/(1 × 10⁻¹²)
[OH⁻] = 0.01 mol·L⁻¹
Moles of OH⁻ = 0.100 L × 0.01 mol/1 L
= 1 × 10⁻³ mol
B. Moles after mixing
H⁺ + OH⁻ ⟶ H₂O
I/mol: 3 × 10⁻³ 1 × 10⁻³
C/mol: -1 × 10⁻³ -1 × 10⁻³
E/mol: 2 × 10⁻³ 0
You have more moles of acid than base, so the base will be completely neutralized when you mix the solutions.
You will end up with 2 × 10⁻³ mol of H⁺ in 200 mL of solution.
C. pH
[H⁺] = (2 × 10⁻³ mol)/(0.200 L)
= 1 × 10⁻² mol·L⁻¹
pH = -log[H⁺
]
= -log(1 × 10⁻²)
= 2