Answer:
No, no precipitate is formed.
Explanation:
Hello there!
In this case, since the reaction between silver nitrate and sodium acetate is:
In such a way, we can calculate the concentration of silver and acetate ions in the solution as shown below, and considering that the final total volume is 50.00 mL or 0.0500 L:
![[Ag^+]=\frac{20.00mL*0.077M}{50.00mL}=0.0308M](https://tex.z-dn.net/?f=%5BAg%5E%2B%5D%3D%5Cfrac%7B20.00mL%2A0.077M%7D%7B50.00mL%7D%3D0.0308M)
![[C_2H_3O_2^-]=\frac{30.00mL*0.043M}{50.00mL}=0.0258M](https://tex.z-dn.net/?f=%5BC_2H_3O_2%5E-%5D%3D%5Cfrac%7B30.00mL%2A0.043M%7D%7B50.00mL%7D%3D0.0258M)
In such a way, we can calculate the precipitation quotient by:
![Q=[Ag^+][C_2H_3O_2^-]=0.0308*0.0258=7.95x10^{-4}](https://tex.z-dn.net/?f=Q%3D%5BAg%5E%2B%5D%5BC_2H_3O_2%5E-%5D%3D0.0308%2A0.0258%3D7.95x10%5E%7B-4%7D)
Which is smaller than Ksp and meaning that the precipitation does not occur.
Regards!
Answer:
It may seem sensible to use a very low temperature in order to maximise the yield of ammonia but lower temperatures reduce the rate of reaction.
Explanation:
Meiosis has two rounds of genetic and cellular division while Mitosis only has one. There are more complicated answers, so i dont know exactly how much info you need.
Answer:
Two
Explanation:
Lone pairs are electron pairs on an atom that resides only with one of the atoms in a molecule.
Dinitrogen pentaoxide is shown in the image attached. There are five oxygen atoms and two nitrogen atoms in the molecule. The molecule has a total of 40 valence electrons.
There are two electrons present on the central oxygen atom in the Lewis structure of dinitrogen pentaoxide as shown in the image attached.
Answer:
1) 10.0 moles of NO
2) 25 moles of NaCl
3) 1200 moles of CO2
1. How many moles of nitrogen monoxide can be made using 5.0 moles of oxygen in the following composition reaction?
N2 + O2 → 2NO
For 1 mol N2 we need 1 mol O2 to produce 2 moles of NO
For 5.0 moles of N2 we need 5.0 moles of O2 to produce 10.0 moles of NO
2. The neutralization of an acid with a base is a double replacement reaction in which a salt and water are formed. If you start with 25 moles of HCl and neutralize it with NaOH how many moles of NaCl will be formed?
HCl + NaOH → NaCl + H2O
For 1 mol HCl we need 1 mol NaOH to produce 1 mol of NaCl and 1 mol H2O
For 25 moles of HCl we need 25 moles of NaOH to produce 25 moles of NaCl and 25 moles of H2O
3. A car burns gasoline (octane – C8H18) with oxygen. If you drive to Salt Lake and burn 150 moles of octane how many moles of carbon dioxide are you producing?
2C8H18 + 25O2 → 16CO2 + 18H2O
For 2 moles of octane we need 25 moles of O2 to produce 16 moles of CO2 and 18 moles of H2O
For 150 moles of octane we need 25*75 = 1875 moles of O2
To produce 16*75 = 1200 moles of CO2 and 18*75= 1350 moles
Explanation:
