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Maslowich
4 years ago
6

How would adding the catalyst nitrogen monoxide (NO) affect this reaction?

Chemistry
2 answers:
marin [14]4 years ago
5 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

A catalyst is defined as the substance which increases the rate of the reaction without actually participating in the reaction.

This substance decreases the activation energy of the reactants, so as to proceed the reaction at a faster rate by increasing their effective collisions.

It does not affect the concentration of the reactants.

For the given reaction:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

If we add NO, which is acting as a catalyst will increase the rate of the reaction to produce the products which is SO_3

Hence, the correct answer is Option A.

Margarita [4]4 years ago
5 0

Answer:

A

Explanation:

Because NO would increase the rate

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NaHCO3 (s) + HC2H3O2 (aq) = NaC2H3O2 (aq) + H2O (I) + CO2 (g)
Misha Larkins [42]

Moles=volume*concentration   
         =0.1*.83
         =.083 Moles of HC2H3O2
Mole ratio between HC2H3O2 and CO2 is 1:1
This means .083 Moles of CO2

Mass =Moles*Rfm of CO2
         =.083*(12+16+16)
         =3.7grams
8 0
4 years ago
Why is terrorism a law enforcement concern?
fomenos
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4 0
3 years ago
Calculate the number of moles when 3.00l of a gas at 814 mmhg and 25 °c?
Mariulka [41]
  • Volume=V=3L
  • Pressure=P=814mmHg
  • Temp=T=25°C

So

No of moles=n

\\ \rm\rightarrowtail PV=nRT

\\ \rm\rightarrowtail n=\dfrac{PV}{RT}

\\ \rm\rightarrowtail n=\dfrac{814(3)}{25R}

\\ \rm\rightarrowtail n=2442/25R

\\ \rm\rightarrowtail n=97.7Rmol

5 0
2 years ago
How many atoms are there in 14.3 g of xenon?
olasank [31]

Answer:

6.56 × 10²² atoms Xe

Explanation:

Step 1: Find conversions

Molar Mass Xe - 131.29 g/mol

Avagadro's Number: 6.022 × 10²³

Step 2: Use Dimensional Analysis

14.3 \hspace{3} g \hspace{3} Xe(\frac{1 \hspace{3} mol \hspace{3} Xe}{131.29 \hspace{3} g \hspace{3} Xe} )(\frac{6.022(10)^{23} \hspace{3} atoms \hspace{3} Xe}{1 \hspace{3} mol \hspace{3} Xe} ) = 6.55911 × 10²² atoms Xe

Step 3: Simplify

We have 3 sig figs.

6.55911 × 10²² atoms Xe ≈ 6.56 × 10²² atoms Xe

8 0
4 years ago
Be sure to answer all parts.
Ede4ka [16]

The Ksp of the solution is 1.97 * 10^-9.

<h3>What is the pH?</h3>

The pH is defined as the hydrogen ion concentration of the solution. Now we have the pH of the solution as 10.9.

We know that;

pOH = 14 - pH

pOH = 14 - 10.9

pOH = 3.1

[OH^-] = Antilog [-3.1]

[OH^-] =7.9 * 10^-4 M

Now

Ksp = [M^2+] [2OH^-]^2

Ksp = s * (2s)^2

Ksp = 4s^3

Now s = 7.9 * 10^-4 M

Ksp = 4(7.9 * 10^-4)^3

Ksp = 1.97 * 10^-9

Learn more about Ksp:brainly.com/question/27132799

#SPJ1

7 0
2 years ago
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