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Maslowich
4 years ago
6

How would adding the catalyst nitrogen monoxide (NO) affect this reaction?

Chemistry
2 answers:
marin [14]4 years ago
5 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

A catalyst is defined as the substance which increases the rate of the reaction without actually participating in the reaction.

This substance decreases the activation energy of the reactants, so as to proceed the reaction at a faster rate by increasing their effective collisions.

It does not affect the concentration of the reactants.

For the given reaction:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

If we add NO, which is acting as a catalyst will increase the rate of the reaction to produce the products which is SO_3

Hence, the correct answer is Option A.

Margarita [4]4 years ago
5 0

Answer:

A

Explanation:

Because NO would increase the rate

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no work was needed. Blinking does not require using energy sometimes we blink without thinking.

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Use the periodic table to identify the element with the electron configuration 1s²2s²2p⁴. Write its orbital diagram, and give th
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Answer:

1. Orbital diagram

2p⁴   ║ ↑↓ ║  "↑"  ║   ↑

2s²    ║ ↑↓ ║

1s²     ║ ↑↓ ║

2. Quantum numbers

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Explanation:

The fill in rule is:

  • Follow shell number: from the inner most shell to the outer most shell, our case from shell 1 to 2
  • Follow the The Aufbau principle, 1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p<7s<5f<6d<7p
  • Hunds' rule: Every orbital in a sublevel is singly occupied before any orbital is doubly occupied. All of the electrons in singly occupied orbitals have the same spin (to maximize total spin).

So, the orbital diagram of given element is as below and the sixth electron is marked between " "

2p⁴   ║ ↑↓ ║  "↑"  ║   ↑

2s²    ║ ↑↓ ║

1s²     ║ ↑↓ ║

The quantum number of an electron consists of four number:

  • <em>n </em>(shell number, - 1, 2, 3...)
  • <em>l</em> (subshell number or  orbital number, 0 - orbital <em>s</em>, 1 - orbital <em>p</em>, 2 - orbital <em>d...</em>)
  • m_{l} (orbital energy, or "which box the electron is in"). For example, orbital <em>p </em>(<em>l</em> = 1) has 3 "boxes", it was number from -1, 0, 1. Orbital <em>d</em> (<em>l </em>= 2) has 5 "boxes", numbered -2, -1, 0, 1, 2
  • m_{s} (spin of electron), either -1/2 or +1/2

In our case, the electron marked with " " has quantum number

  • <em>n </em>= 2, shell number 2,
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  • m_{l} = 0, 2nd "box" in the range -1, 0, 1
  • m_{s} = +1/2, single electron always has +1/2
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