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3 years ago

How would adding the catalyst nitrogen monoxide (NO) affect this reaction?

Chemistry

2 answers:

marin [14]3 years ago

5 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

A catalyst is defined as the substance which increases the rate of the reaction without actually participating in the reaction.

This substance decreases the activation energy of the reactants, so as to proceed the reaction at a faster rate by increasing their effective collisions.

It does not affect the concentration of the reactants.

For the given reaction:

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$

If we add NO, which is acting as a catalyst will increase the rate of the reaction to produce the products which is $SO_3$

Hence, the correct answer is Option A.

Margarita [4]3 years ago

5 0

Answer:

Explanation:

Because NO would increase the rate

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Alexandra [31]

Answer:

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Explanation:

Weight=Mass*Gravity

440.55=m*9.8

Make m the subject

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3 years ago

After stirring the sugar you added to some hot tea, the sugar disappears but the tea tastes sweet.

kirza4 [7]

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3 years ago

On the addition of HI

victus00 [196]

Answer:

$CH_3-CH(I)-CH(CH_3)-CH_3$

$I-CH_2-CH_2-CH(CH_3)-CH_3$

Explanation:

Given the compound $CH_2=CH-CH(CH_3)-CH_3$

The steps of reaction:

$HI \longrightarrow H^+ + I^-$

$CH_2=CH-CH(CH_3)-CH_3 + H^+ \longrightarrow CH_3-CH^+-CH(CH_3)-CH_3$

<u>But this intermediate product has a resonance: </u>

$CH_3-CH^+-CH(CH_3)-CH_3 \longleftrightarrow C^+H_2-CH2-CH(CH_3)-CH_3$

The reaction with I-

$CH_3-CH^+-CH(CH_3)-CH_3 + I^- \longrightarrow CH_3-CH(I)-CH(CH_3)-CH_3$

$C^+H_2-CH2-CH(CH_3)-CH_3 + I^- \longrightarrow I-CH_2-CH_2-CH(CH_3)-CH_3$

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3 years ago

Oil and water a combined to make salad dressing.

maks197457 [2]

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3 years ago

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Phosphine (PH3) can be prepared by the reaction of calcium phosphide , Ca3P2: based on this equation : Ca3P2 + 6H2O —-> 3 Ca(

MrMuchimi

Taking into account the reaction stoichiometry, you can observe that:

one mole of Ca₃P₂ produces 2 mol of PH₃.
the mole ratio between phosphine and calcium phosphide is 2 mol PH₃ over 1 mol Ca₃P₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Ca₃P₂ + 6 H₂O → 3 Ca(OH)₂ + 2 PH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Ca₃P₂:1 mole
H₂O: 6 moles
Ca(OH)₂: 3 moles
PH₃: 2 moles

The molar mass of the compounds is:

Ca₃P₂: 182 g/mole
H₂O: 18 g/mole
Ca(OH)₂: 74 g/mole
PH₃: 34 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Ca₃P₂: 1 mole ×182 g/mole= 182 grams
H₂O: 6 moles× 18 g/mole= 108 grams
Ca(OH)₂: 3 moles ×74 g/mole= 222 grams
PH₃: 2 moles ×34 g/mole= 68 grams

<h3>Correct statements</h3>

Then, by reaction stoichiometry, you can observe that:

one mole of Ca₃P₂ produces 2 mol of PH₃.
the mole ratio between phosphine and calcium phosphide is 2 mol PH₃ over 1 mol Ca₃P₂.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

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2 years ago