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fiasKO [112]
3 years ago
13

If the inital pressure of an ideal gas at a temperature of 344 K is 0.917 atm, what is the pressure of the gas at 322 K?

Chemistry
1 answer:
Gennadij [26K]3 years ago
8 0

Answer:  P2 = 0.858 atm

Explanation:

Use the combined gas law:  P1V1/T1 = P2V2/T2,

where the subscripts are the initial (1) and final (2) states.  Temperature must be in Kelvin.  We want P2, so rearrange the equation to solve for P2:

P2 = P1(V1/V2)(T2/T1)

Note how I've arranged the volume and temperature values:  as ratios.  Now it is easy to cancel units and see what is going to happen to the pressure if we lower the temperature.  Since the pressure change is a function of (T2/T1), and we are lowering the temperature (T2), we'd expect this to decrease the pressure.

No information is given on volume, so we'll assume a convenient value of 1 liter.  Now enter the data:

P2 = (0.917atm)*(1)*(322K/344K)

P2 = 0.858 atm

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