Answer: 4
Step-by-step explanation:
18-14=4
suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
In this question, both tickets cost 2$ per ticket.
The answer to this question would be: $0
In WinOne scenario, you need to match a ticket that has to pick from A-J(10 possibilities) and 0-9 (10 possibilities). The chance to win would be: 1/10* 1/10= 1/100
The expected value must be:
E= chance to win * win amount - ticket price
E= 1//100*$200 - $2= $2-$2= 0
Answer
14.4 ft~
Step-by-step explanation
A kite is flying 12 feet off the ground, therefore the height is 12 (assuming the line is tied to the ground if a person is holding the line then the height would be less)
Assuming the sun is positioned in such a way that the shadow represents a horizontal distance. Horizontal distance of shadow = 8
Use Pythagoras Theorem
Where a^2 + b^2 = c^2
8^2 + 12^2 = 208
Square root 208 = 14.4~
~ Hoodini, here to help :)