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4 years ago

Guess and write what would happen if either magnitude scale is greater than 8?

1 answer:

8 0

Earthquake size, as measured by the Richter Scale is a well known, but not well understood, concept. The idea of a logarithmic earthquake magnitude scale was first developed by Charles Richter in the 1930's for measuring the size of earthquakes occurring in southern California using relatively high-frequency data from nearby seismograph stations. This magnitude scale was referred to as ML, with the L standing for local. This is what was to eventually become known as the Richter magnitude

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How does electric force depend on the amount of charge and the distance between charges

Gennadij [26K]

Explanation:

The attractive or repulsive forces which act between any two charged species is an electric force.
The electric force depends on the distance between the charged species and the amount of charge which can be calculated by the formula given as follows

F = k× $\frac{q1q2}{r2}$

where, K is coulombs constant, which is equal to - 9 x10^9 $Nm^2/C^2.$

The unit for K is newtons square meters per square coulombs.
This is known as Coulomb's Law.

6 0

3 years ago

Suppose the moon were held in its orbit not by gravity but by the tension in a massless cable. You are given that the period of

Ksenya-84 [330]

Answer:

Tension in the cable = 200.655 × 10^(18) N

Explanation:

The tension in the cable will be the force on the string which is caused by when it holds against the centripetal acceleration.

Now, the formula for centripetal acceleration is given by;

a = v²/R

Now, let's find the velocity.

The circumference is 2πR

We are given that R = 3.85 x 10^(8) m

So, Circumference = 2 × π × 3.85 x 10^(8) = 24.19 × 10^(8) m

We are told the period of the moon orbit is 27.3 days

Distance travelled per day = Circumference/ period

Distance travelled per day = (24.19 × 10^(8))/27.3 = 88608058.608 m/day

Now, a day has 24 hours = 24 × 60 × 60 = 86400 seconds

Thus,

Distance travelled per seconds =

88608058.608/86400 = 1025.556 m/sec

So, from a_c = v²/r,

a_c = 1025.556²/3.85x10^8

a_c = 0.00273 m/s²

Now, Force = Mass x Acceleration = ma

We are given mass = 7.35 x 10^(22) kg

Plugging in the relevant values, we have;

F = 0.00273 x 7.35 x 10^(22)

F = 200.655 × 10^(18) N

5 0

3 years ago

An arrow of mass 0.5kg so it has 25J of kinetic energy; find the speed of the arrow v = m/s

miss Akunina [59]

Answer:

10 m/s

Explanation:

Use the kinetic energy formula:

KE=(1/2)mv^2

I always remember it as Kevin is half-mad, and very square.

25J = (1/2)*0.5kg*(v^2)

50J = 0.5kg*(v^2)

100J = v^2

v = 10 m/s

Check it:

KE = (1/2)*0.5*(10^2)

KE = 25J

yep, it's right!

4 0

3 years ago

2350m = is how many kilameters

Aloiza [94]

Answer:

2.35 killometers

Explanation:

4 0

3 years ago

HELP FOR POINTS PLEASE

alukav5142 [94]

Explanation:

a wind breaker .......

6 0

4 years ago

Read 2 more answers

Guess and write what would happen if either magnitude scale is greater than 8?​

Guess and write what would happen if either magnitude scale is greater than 8?