Answer:
6m/s
Explanation:
A slower moving car is traveling behind a faster moving bus. The velocities of the two vehicles are: vCG = velocity of the Car relative to the Ground = +12 m/s vBG = velocity of the Bus relative to the Ground = +16 m/s A passenger on the bus gets up and walks toward the front of the bus with a velocity of vPB, where vPB = velocity of the Passenger relative to the Bus = +2 m/s What is vPC, the velocity of the Passenger relative to the Car?
When you are is in a car moving with 12m/s speed and then there is a bus moving with 16m/s in front of you. Of course, the bus is 4m/s faster than you. if a passenger in the bus stands and runs towards the front of the bus with a speed of 2m/s , he is 2m/s ahead +the 4m/s the bus was already ahead of you, mathematically
Vpg=speed of the passenger relative to the ground
Vpb=sped of the passenger relative to the bus
Vbc=speed of the bus relative to the car
Vbg=speed of the bus relative to the ground
Vpg=Vpb+Vbc
Vbc=Vbg+Vgc
so we can conclude that
Vpc=Ypb+Vbg+Vgc
Vpc=2+16-12
Ypc=6m/s