The object takes 0.5 seconds to complete one rotation, so its rotational speed is 1/0.5 rot/s = 2 rot/s.
Convert this to linear speed; for each rotation, the object travels a distance equal to the circumference of its path, or 2<em>π</em> (1.2 m) = 2.4<em>π</em> m ≈ 7.5 m, so that
2 rot/s = (2 rot/s) • (2.4<em>π</em> m/rot) = 4.8<em>π</em> m/s ≈ 15 m/s
thus giving it a centripetal acceleration of
<em>a</em> = (4.8<em>π</em> m/s)² / (1.2 m) ≈ 190 m/s².
Then the tension in the rope is
<em>T</em> = (50 kg) <em>a</em> ≈ 9500 N.
. we need like a picture you something what’re you trying to ask
<span>a system of millions or billions of stars, together with gas and dust, held together by gravitational attraction.</span>
Answer:
The pressure corresponding to the absolute zero temperature is 0.997atm.
Explanation:
To solve this question, you draw a straight vertical line with the boiling point temperature and pressure on top of the line and the freezing point temperature and pressure on the lower part. The absolute temperature somewhere in the middle of the line with the pressure to be obtained.
So, we have;
0- (-19) / 100 - (-19) = P - 0.9267 / 1.366 - 0.9267
19 / 119 = P - 0.9267 / 0.4393
Cross multiply, we have
19 * 0.4393 = 119(P -0.9267)
8.3467 = 119P - 110.2773
119P = 118.624
P = 0.997 atm
So at 0°C, the pressure of the thermometer is 0.997atm.
